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zmey [24]
3 years ago
9

Solve for x; 7x + 9 = 2(4x + 2) Please show your work, will vote for the brainiest answer.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0
<span>7x+9=2(4x+2) 
7x+9=8x+4
7x-8x=4-9
-x=-5
x=-5/-x
x=5

</span>
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use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r
Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt

If we ask that f has continuous (n+1)th derivative we can apply the mean value theorem for integrals. Then, there exists c between a and x such that

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x

Hence,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .

Thus,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}

and the Taylor theorem with Lagrange remainder is

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}.

Step-by-step explanation:

5 0
3 years ago
HELP I NEED HELP ASAP
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Answer: Quora. It will help, trust me or search it up

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BlackZzzverrR [31]

Answer:

In the fraction 41/100, 41 is the numerator and 100 is the denominator, the fraction bar means "divided by". So to convert 41/100 as decimal number we simply divide the numerator by denominator.

When we calculated 41 divided by 100, we found that 41/100 in decimal form is:

41 ÷ 100 = 0.41

Therefore, the decimal equivalent of 41/100 is 0.41

Step-by-step explanation:

Hope it is helpful....

8 0
3 years ago
Read 2 more answers
One of the roots of the equation x2−5x+q=0 is 2. Find the other root and the value of the coefficient q.
pishuonlain [190]

Answer:

q=6

Step-by-step explanation:

A root can be plugged in for X, so 2(2)-5(2)+q=0. This means -6+q=0. We can now even them out and know q=6

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kvasek [131]
56 would be your answer because it’s the lowest number
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