Answer:
Option 4 is correct. The length of PR is 6.4 units.
Step-by-step explanation:
From the given figure it is noticed that the triangle PQR and triangle MQR.
Let the length of PR be x.
Pythagoras formula
![hypotenuse^2=base^2+perpendicular^2](https://tex.z-dn.net/?f=hypotenuse%5E2%3Dbase%5E2%2Bperpendicular%5E2)
Use pythagoras formula for triangle PQM.
![PM^2=QM^2+PQ^2](https://tex.z-dn.net/?f=PM%5E2%3DQM%5E2%2BPQ%5E2)
![PM^2=(6)^2+(8)^2](https://tex.z-dn.net/?f=PM%5E2%3D%286%29%5E2%2B%288%29%5E2)
![PM^2=36+64](https://tex.z-dn.net/?f=PM%5E2%3D36%2B64)
![PM^2=100](https://tex.z-dn.net/?f=PM%5E2%3D100)
![PM=10](https://tex.z-dn.net/?f=PM%3D10)
The value of PM is 10. The length of PR is x, so the length of MR is (10-x).
Use pythagoras formula for triangle PQR.
![PQ^2=QR^2+PR^2](https://tex.z-dn.net/?f=PQ%5E2%3DQR%5E2%2BPR%5E2)
![(8)^2=QR^2+x^2](https://tex.z-dn.net/?f=%288%29%5E2%3DQR%5E2%2Bx%5E2)
.....(1)
Use pythagoras formula for triangle MQR.
![MQ^2=QR^2+MR^2](https://tex.z-dn.net/?f=MQ%5E2%3DQR%5E2%2BMR%5E2)
![(6)^2=QR^2+(10-x)^2](https://tex.z-dn.net/?f=%286%29%5E2%3DQR%5E2%2B%2810-x%29%5E2)
![36=QR^2+x^2-20x+100](https://tex.z-dn.net/?f=36%3DQR%5E2%2Bx%5E2-20x%2B100)
.... (2)
From equation (1) and (2) we get
![36-x^2+20x-100=64-x^2](https://tex.z-dn.net/?f=36-x%5E2%2B20x-100%3D64-x%5E2)
![20x-64=64](https://tex.z-dn.net/?f=20x-64%3D64)
![20x=128](https://tex.z-dn.net/?f=20x%3D128)
![x=6.4](https://tex.z-dn.net/?f=x%3D6.4)
Therefore length of PR is 6.4 units and option 4 is correct.
(0,4)(2,-3)
slope = (-3 - 4) / (2 - 0) = -7/2
Answer:
70
Step-by-step explanation:
Ok so we first add 4.75 and 5.25. 4.75+5.25=10. So 10 hours each day so 10 x 7 = 70. 70 hours in 7 days
Extra 10, 10 is half of what she ordered so she received an extra 50%
Answer:
--- You
--- Another student
Reason: Because there is a variation in the given dimensions
Step-by-step explanation:
Given
Your measurement
![Length = 20.70cm; Width =10.44cm](https://tex.z-dn.net/?f=Length%20%3D%2020.70cm%3B%20Width%20%3D10.44cm)
Another students'
![Length = 20.74cm; Width =10.46cm](https://tex.z-dn.net/?f=Length%20%3D%2020.74cm%3B%20Width%20%3D10.46cm)
Solving (a): The area
Area is calculated as:
![Area = Length * Width](https://tex.z-dn.net/?f=Area%20%3D%20Length%20%2A%20Width)
For you
![Area = 20.70cm * 10.44cm](https://tex.z-dn.net/?f=Area%20%3D%2020.70cm%20%2A%2010.44cm)
![Area = 216.108cm^2](https://tex.z-dn.net/?f=Area%20%3D%20216.108cm%5E2)
For the other student
![Area = 20.74cm * 10.46cm](https://tex.z-dn.net/?f=Area%20%3D%2020.74cm%20%2A%2010.46cm)
![Area = 216.940cm^2](https://tex.z-dn.net/?f=Area%20%3D%20216.940cm%5E2)
Solving (b): Reason for the variation in the areas
The given measurements are estimates of the dimensions of the rectangle.
Since there is a variation in the estimates, there will be some level of variation in the calculated area.