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77julia77 [94]
4 years ago
10

Answer this fast hurry​

Mathematics
2 answers:
saveliy_v [14]4 years ago
8 0

ans is 2 m^2, as it's a rectangle in shape and area of a rectangle is length x width

Zarrin [17]4 years ago
6 0

Answer:

2          

Step-by-step explanation:

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A car is driving down I-55 approaching the exit for two cities: Angleton and Bisectorville. Both towns are 3.14 miles to I-55 an
Shtirlitz [24]

Answer:

3.14 mile-55=51.86 miles from the car and exit

i think i help.(sorry if it is not correct)

Step-by-step explanation:

7 0
3 years ago
For the given angle 0, identify the reference angle, _
ankoles [38]

Answer:

π\6

Step-by-step explanation:

The reference angle is the smallest angle measured from the terminal side of the angle (where the angle ends) to the x axis. The reference angle is an acute angle (i.e less than 90° or π/2)

For O = 11π/6 = 1.833π

1.833π is in the fourth quadrant between 3π/2 radians and 2π radians. Since it is in the fourth quadrant, the reference angle is given as:

reference angle = 2π - 11π/6 = π\6

5 0
3 years ago
Estimate the area of a circle with a radius of 3.1 feet
Aliun [14]

Answer:

Step-by-step explanation:

Area of a circle = pi x square of radius = 30.190 ft

5 0
4 years ago
An inch is equal to about 2.54 centimeters. Write an expression who he estimates the number of centimeters in x inches. Then est
trasher [3.6K]

There are 30.48 centimeters in 12 inches.

Step-by-step explanation:

Given,

1 inch = 2.54 centimeters

For x inches;

x inches = 2.54*x centimeters

x inches = 2.54x centimeters

Number of centimeters in 12 inches

We will put x=12

12 inches = 2.54(12) centimeters

12 inches = 30.48 centimeters

There are 30.48 centimeters in 12 inches.

Keywords: multiplication

Learn more about multiplication at:

  • brainly.com/question/10744457
  • brainly.com/question/10754198

#LearnwithBrainly

5 0
4 years ago
Is the quotient 3.6÷9 greater or less than one
anastassius [24]
3 6/10÷ 9
36/10×1/9
36/90
.4<1

(Less than)

Hope this helps!
3 0
3 years ago
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