in how many ways can a mail carrier place three letters in five mailboxes if each box may receive more than one letter?

The trigonometric form of a complex number is unique - True or false?

svp [43]

The answer is False
I hope that helped

3 0

3 years ago

What is 80 x 40? Make 5 paragraphs stating the answer.

MariettaO [177]

80 x 40 is 320. I know 80 x 40 is 320 because 80 + 80 + 80 + 80 is 320. I also know 80 x 40 is 320 because 8 x 4 is 36. If you pretend the 0 is not there it’s 8 x 4. I know you can get the answer quicker that way because it’s just times tables.

7 0

2 years ago

You deposit $100 in a savings account. The account earns 11% simple interest per year.

Gnesinka [82]

Answer:

Step-by-step explanation:

<h3>principle ( p ) = $100</h3><h3>time ( t ) = 10 years </h3><h3>rate ( r ) = 11%</h3><h3>simple interest = (p × r × t)÷ 100</h3><h3> = ( $100 × 11 × 10 )÷ 100</h3><h3> = 11000 ÷ 100</h3><h3> = $110</h3>

<h3>interest = simple interest - principle </h3><h3>interest = $110 - $100</h3><h3> = $10</h3>

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5 0

2 years ago

The cost of oranges in a grocery store is directly proportional to the number of oranges purchased. Jerri payed $2.52 for 6 oran

ExtremeBDS [4]

Answer: option A is the correct answer.

Step-by-step explanation:

The cost of oranges in a grocery store is directly proportional to the number of oranges purchased. Jerri paid $2.52 for 6 oranges.

If p represents the cost, in dollars,and n represents the number of oranges purchased, then introducing a proportionality constant, k, the equation becomes

p = kn

2.52 = k × 6

k = 2.52/6 = 0.42

Therefore, the equation representing the relationship is

p = 0.42n

4 0

3 years ago

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

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