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babunello [35]
3 years ago
11

Please answer this question now

Mathematics
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

Measure of arc CD = 112°

Step-by-step explanation:

Since quadrilateral ABCD is a cyclic quadrilateral,

m∠A + m∠C = 180°

129° + m∠C = 180°

m∠C = 180° - 129°

m∠C = 51°

Since, m(arc BD) = 2(m∠C) [Since measure of the arc is double of its inscribed angle]

                           = 2(51°)

                           = 102°

Since, m(arc BD) + m(arc CD) + m(arc BC) = 360°

102° + m(arc CD) + 146° = 360°

m(arc CD) = 360° - (102° + 146°)

                = 112°

Therefore, measure of arc CD is 112°.

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If z = 2, find the value of: a. 6z2–2z+5<br> b. 64–5z
Ludmilka [50]

Answer:

25 and 54

Step-by-step explanation:

(a)

6z² - 2z + 5 ← substitute z = 2

= 6(2)² - 2(2) + 5

= 6(4) - 4 + 5

= 24 - 4 + 5

= 20 + 5

= 25

(b)

64 - 5z ← substitute z = 2

= 64 - 5(2)

= 64 - 10

= 54

4 0
3 years ago
Peter is reading a 193-page book. He has read three pages more than one-fourth of the number of pages he hasn’t yet read. How ma
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5 0
3 years ago
Read 2 more answers
What is the difference between x and dx?
N76 [4]

This response is based upon your having had some background in calculus. "dx" is not introduced before that.

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Now, for a big jump: we consider finding the area under a curve (graph) between x = a and x = b. We subdivide that interval [a,b] into n vertical slices of area. Each of those slices has its own area: f(x)*dx, where dx represents the width of such subarea. f(x)*dx is the actual subarea. To find the total area under the curve f(x) between x= a and x = b, we add up all of these individual subareas between x = a and x = b. Note that the subinterval width is

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8 0
3 years ago
I need help on number 16
ollegr [7]
There will be two squares.

Think about it: The shorter side is 3.5 feet. The longer side is 7 feet. If he cuts it in half on the longer side, he's taking the length of that longer side, and dividing it by 2. 7/2=3.5.

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I believe it would be the second option....
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