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3 years ago

Expand and simplify (2x+2)(2x+1)

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

8 0

Answer:

4x^2+6x+2

Step-by-step explanation:

Korolek [52]3 years ago

7 0

Answer: 4x+3

Step-by-step explanation: 2x+2x=4x

2x1=3

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Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to

mezya [45]

Answer:

The confidence interval is (24116.3878,24883.6122).

Step-by-step explanation:

We are given the following information in the question:

Population mean, $\mu$ = $23,500

Sample mean, $\bar{x}$ = $24,500

Sample standard deviation,s = $2,800

Sample size, n = 146

Confidence interval:

$\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at}~\alpha_{0.05} = \pm 1.655436$

$24500 \pm 1.65543(\frac{2800}{\sqrt{146}} ) = 24500 \pm 383.6122 = (24116.3878,24883.6122)$

The confidence interval is (24116.3878,24883.6122).

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3 years ago

www.g A bag contains 3 white counters, 10 black counters, and 4 green counters. What is the probability of drawing (a) a white c

erastovalidia [21]

Answer:

41.18% probability of drawing a white counter or a green counter

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

There are 3+10+4 = 17 counters.

Of those, 3+4 = 7 are white or green

7/17 = 0.4118

41.18% probability of drawing a white counter or a green counter

4 0

3 years ago

2.8 -3x =12.1 −6x what's x

Kipish [7]

X= 3.1 is the answer

6 0

3 years ago

Read 2 more answers

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$