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AnnZ [28]
3 years ago
9

A person with too much lactic acid in their blood, formally called lactic acidosis, is at risk for a variety of adverse health e

ffects. If the average person has approximately 4445 mL of blood, how much lactic acid (in grams) would there need to be before the healthy range is exceeded?
Chemistry
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

Lactic acidosis occurs when there is greater than 1.60 g in 4445 mL of blood

Explanation:

A normal blood lactic acid level is 0.5-1 mmol/L.

Mild to moderately elevated level of blood lactic acid known as hyperlactatemia occur when the range is between 2-4 mmol/L without metabolic acidosis.

Lactic acidosis occurs with blood lactic acid levels of > 4 mmol/L

Molar mass Lactic acid, C₃H₆O₃ = 90 g/mol

Mass 4 mmol lactic acid = 0.004 mol * 90 g/mol = 0.36 g

Mass of lactic acid in 1 litre or 1000 mL of blood = 0.36 g

Mass  of lactic acid in 4445 mL of blood = 0.36 g * (4445/1000)

<em>Mass  of lactic acid in 4445 mL of blood = 1.60 g</em>

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How many moles are in a mass of 800.0 g of magnesium?
qaws [65]

Answer:

32.92 moles of Mg

Explanation:

To convert grams to moles (Or vice versa) of any chemical compound we need to use the molar mass of the substance (That is, how many grams weighs 1 mole of the chemical).

The magnesium, Mg, has a molar mass of 24.305g/mol. That means in 800.0g of Mg you have:

800.0g * (1mol / 24.305g) =

<h3>32.92 moles of Mg</h3>
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3 years ago
What are 2 diseases caused by coronaviruses?
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SARS and MERS

Explanation:

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3 years ago
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Which shows the rational expression written using the least common denominator?
Alexandra [31]

Answer:

The first one.

\frac{x + 1}{4x^{2} } and \frac{4(x + 1)}{4x^{2} }

Explanation:

When comparing two fractions with variables like this, it's important to get to the same denominator in order to compare apples with apples and then be able to do not only comparisons but also perform additions/subtractions.

Question is which denominator to use and how to reach it.

In this case, the question and the answer choices do the work for you.  The question asks which one is the LEAST common denominator, and the answers show denominators x² and 4x².  The smallest of these is x², however, we can't simplify the first fraction to get to the x² denominator, so we'll go for the 4x².

So, the first fraction has already the correct denominator (4x²), we just have to transform the second one.

We multiply it by 1, expressed in a different way.  Since we're multiplying by one, we're not affecting the value, just the way it looks.

Let's do it!, to get the denominator to go from x² to 4x², we need to multiply it by 4... so we'll multiply by 4/4 (which is 1, neutral for the multiplication).

\frac{x + 1}{x^{2} } * \frac{4}{4} = \frac{4(x + 1)}{4x^{2} }

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6 0
3 years ago
A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre
givi [52]

Answer:

\mathbf{0.02 M}

Explanation:

\text{So, from the given question:}

\text{EDTA will make complex with} V^{+3} \text{and the remaining EDTA will react with }Ga^{+3}

\text{Hence, the total concentration of} V^{+3} & Ga^{+3} \text{will be equivalent to EDTA concentration.}

V_{EDTA} = 25 \ mL

V_{V^{+3}} = 59.0 \ mL

V_{Ga^{+3}} = 13.0 \ mL

M_{EDTA} = 0.0680 \ M

M_{V^{+3}} = ???(unknown)

M_{Ga^{+3}} = 0.0400 \ M

V^{+3} + EDTA \to V[EDTA] + EDTA(Excess)  \to^{CoA} \ Ga[EDTA] _{complex}

M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})

0.0680 \times 25 = (59\times x + 13 \times 0.040) \\ \\ 1.7 = 59x + 0.52\\ \\ 1.7 - 0.52 = 59x \\ \\ 59x = 1.18

x = \dfrac{1.18}{59}

\mathbf{x =0.02 \ M }

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3 years ago
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Gas !!
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Gas
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3 years ago
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