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aksik [14]
3 years ago
15

WARMING OCEAN TEMPERAUTRE AFFECTS THE BIODIVERSITY OF ORGANISMS. WHICH OF THE FOLLOWING DISRUPTIONS WOULD YOU EXPECT TO SEE IN A

POPULATION 0F NORTHERN WHALES AS A RESULT OF WARMER OCEAN WATER?
Chemistry
1 answer:
Ilya [14]3 years ago
7 0

Climate change greatly affects the community of whales and dolphins. Most of the species of whales live in a specific temperature range, because of the non-availability of their food, zoo plankton in warm waters. One of the most important organisms whales prey up on are zoo plankton, whose number declined greatly due to the warming of oceans. These whales migrate to Northern waters overcome the effects of increasing temperature and in search of food. So ,we can expect a disruption in the food chain as a result of the warm oceanic waters.

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Which compound are ionic and which are covalent? (N2) (CCl4) (SiO2) (AlCl3) (CaCl2) (LiBr)
muminat
Covalent compounds: N2, CCl4, SiO2 and AlCl3.

Ionic compounds: CaCl2 and LiBr.

Hope this helps!
3 0
3 years ago
How are parentheses used in chemical formulas
Liula [17]
They make the symbols individual
6 0
3 years ago
How many hydrogen atoms are in each molecule of trisilylamine?
lord [1]

Answer:

  • <u>9</u>

Explanation:

The amine functional group is obtained by subsititution of one or more hydrogen atoms in the ammonia compound.

Ammonia is NH₃.

Then,

  • by substituting one hydrogen you obtain R - NH₂.

  • by substituting two hydrogens you obtain R' - NH - R''

  • by subsituting the three hydrogens you obtain:

                        R'''

                         |

                 R' -  N - R''

In this case, the three subsitutuents are silyl groups. The silyl group is derived form silane and is SiH₃. So, the tcompound <em>trisilylamine</em> is:

                    SiH₃

                      |

          SiH₃ -  N - SiH₃

Thus, you can count 3 hydrogen atoms for every silylgroup for a total of <u><em>9 hydrogen atoms in each molecule of trisilylamine.</em></u>

7 0
3 years ago
Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?
iVinArrow [24]

The  number of atoms  of K that are in 235 g  of the compound  is

2.57 x10^24 atoms


 calculation

Step 1:  find the moles of K2S

= moles = mass/molar mass

=  235 g/110 g/mol= 2.136  moles

Step 2: multiply  2.136 moles  by no. of K atoms in K2S

= 2.136  x2 = 4.272 moles


Step 3: use the Avogadro's  law to determine number of K atoms

that is according to Avogadro's law  1 mole = 6.02 x 10^23  atoms

                                                            4.272 moles= ? atoms

by cross multiplication

= (4.272  moles x 6.02 x10^23 atoms)  / 1 mole = 2.57 x10^24 atoms

4 0
3 years ago
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H2SO4(aq)? For your ans
Alik [6]

Question is incomplete, complete question is;

A 34.8 mL solution of H_2SO_4 (aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).

H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H_2SO_4(aq)? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.

Answer:

0.044 M is the molarity of H_2SO_4(aq).

Explanation:

The reaction taking place here is in between acid and base which means that it is a neutralization reaction .

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_1,M_2\text{ and }V_2  are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=34.8 mL\\n_2=1\\M_2=0.15 M\\V_2=20.4 mL

Putting values in above equation, we get:

2\times M_1\times 34.8 mL=1\times 0.15 M\times 20.4 mL\\\\M_1=\frac{1\times 0.15 M\times 20.4 mL\times 10}{2\times 34.8 mL}=0.044 M

0.044 M is the molarity of H_2SO_4(aq).

4 0
3 years ago
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