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kifflom [539]
3 years ago
15

How many moles are in a mass of 800.0 g of magnesium?

Chemistry
1 answer:
qaws [65]3 years ago
7 0

Answer:

32.92 moles of Mg

Explanation:

To convert grams to moles (Or vice versa) of any chemical compound we need to use the molar mass of the substance (That is, how many grams weighs 1 mole of the chemical).

The magnesium, Mg, has a molar mass of 24.305g/mol. That means in 800.0g of Mg you have:

800.0g * (1mol / 24.305g) =

<h3>32.92 moles of Mg</h3>
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Given a certain quantity of reactant, you calculate that a particular
zlopas [31]

Answer:

Percent yield =  114.5%

Explanation:

Given data:

Calculated amount of product/ theoretical yield = 55 g

Actual amount of product after performing reaction = 63 g

Percent yield = ?

Solution:

Formula:

Percent yield = ( actual yield / theoretical yield )× 100

by putting values,

Percent yield = (63 g/ 55 g)× 100

Percent yield =  114.5%

4 0
3 years ago
Rxn
givi [52]

Answer: The enthalpy of formation of SO_3 is  -396 kJ/mol

Explanation:

Calculating the enthalpy of formation of SO_3

The chemical equation for the combustion of propane follows:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]

We are given:

\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-297kJ/mol\\\Delta H^o_{rxn}=-198kJ

Putting values in above equation, we get:

-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol

The enthalpy of formation of SO_3 is -396 kJ/mol

4 0
3 years ago
IMMA WAIT FOR MY BABY EVEN IF IT TAKES ALL NIGHT !!!!!!
saul85 [17]

Answer:

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Explanation:

3 0
3 years ago
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Be sure to answer all parts. Compounds a and b are isomers having molecular formula c5h12. Heating a with cl2 gives a single pro
Elden [556K]

Neo-pentane represents the Compound A while compound B is n-pentane.

After careful consideration we can say that compounds A and B are alkanes and also isomers of pentane. In chemistry, Isomers are defined as compounds having same empirical molecular formula but different structural formulas due to varying arrangement of atoms.

Now, as per the question statement, compound A gives a single monochlorination product upon heating with the molecule of chlorine i.e. Cl2 showing that the molecule is extremely symmetric. This molecule must be neo-pentane. Refer to image 1.

Similarly, Compound B forms 3 constitutional isomers after undergoing monochlorination. This compound must be n-pentane since three are 3 different types of carbon atoms in the structure. Refer to image 2.

If you need to learn more about neo-pentane click here:

brainly.com/question/20815247

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3 0
1 year ago
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Analysis of a compound of sulfur, oxygen and fluorine showed that it is 31.42% S and 31.35% O, with F accounting for the remaind
Leya [2.2K]

Answer:

The molecular formula is  SO2F2

Explanation:

Step 1: Data given

Suppose the mass of compound = 100 grams

The compound contains:

31.42 % S = 31.42 grams S

31.35 % O = 31.35 grams O

100 - 31.42 - 31.35 = 37.23 F

Molar mass of S = 32.065 g/mol

Molar mass F = 19.00 g/mol

Molar mass O = 16.00 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles S = 31.42 grams / 32.065 g/mol

Moles S = 0.9799 moles

Moles 0 = 31.35 grams / 16.00 g/mol

Moles 0 = 1.959 moles

Moles F = 37.23 grams / 19.00 g/mol

Moles F = 1.959 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

S: 0.9799 / 0.9799 = 1

F: 1.959/ 0.9799 = 2

O : 1.959 / 0.9799 = 2

The empirical formula is SO2F2

This formula has a molecular mass of 102.06 g/mol

This means the empirical formula is also the molecular formula : SO2F2

3 0
3 years ago
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