How many moles are in a mass of 800.0 g of magnesium?
1 answer:
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Answer: Resulting solution will not be neutral because the moles of ions is greater. The remaining concentration of
ions =0.0058 M.
Explanation:
Given,
[HCl]=0.100 M
= 0.200 M
=0.0100 M
[RbOH] =0.100 M
Few steps are involved:
Step 1: Calculating the total moles of ion from both the acids
moles of in HCl
if 1 L of solution =0.100 moles of HCl
then 0.05L of HCl solution= 0.05 0.1 moles= 0.005 moles (1L=1000mL)
moles of in HCl = 0.005 moles
Similarliy
moles of in
If 1L of solution= 0.200 moles
Then 0.1L of solution= 0.1
0.200 moles= 0.02 moles
moles of in
=0.02 moles
so, Total moles of ions = 0.005+0.02= 0.025 moles .....(1)
Step 2: Calculating the total moles of ion from both the bases
Moles of
1 L of = 0.0100 moles
Then in 0.5 L solution = 0.5
0.0100 moles = 0.005 moles
produces two moles of
ions
moles of = 0.005
2= 0.01 moles
Moles of in
1 L of RbOH= 0.100 moles
then 0.2 [RbOH] solution= 0.2 0.100 moles = 0.02 moles
Moles of = 0.02 moles
so,Total moles of ions = 0.01 + 0.02=0.030 moles ....(2)
Step 3: Comparing the moles of both ions
One mole of ions will combine with one mole of
ions, so
Total moles of ions = 0.005+0.02= 0.025 moles....(1)
Total moles of ions = 0.01 + 0.02=0.030 moles.....(2)
For a solution to be neutral, we have
Total moles of ions = total moles of
ions
0.025 moles will neutralize the 0.025 moles of
Moles of ions is in excess (from 1 and 2)
The remaining moles of will be = 0.030 - 0.025 = 0.005 moles
So,The resulting solution will not be neutral.
Remaining Concentration of ions =
Explanation:
Amount of water required in each case:
(a)The mass% of the solution is:9.95
Mass of solute that is urea is 6.80 g
To determine the mass of solvent water use the formula:
Hence the mass of solvent = mass of solution - the mass of solute
=68.3 g - 6.80g
=61.5 g
Hence, the answer is mass of solvent water required is 61.5 g.
(b) Given mass%=1.70
mass of solute MgBr2 = 29.3 g
The mass of solvent water required can be calculated as shown below:
The mass of the solution is 1720 g.
Mass of solvent water = mass of solution - mass of solute
=1720 g - 29.3 g
=1690.7 g
Answer: The mass of water required is 1690.7 g.