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inysia [295]
3 years ago
6

Ben bought a laptop that was 15% off the regular price of $999. If a 8% sales tax was added to the cost of the laptop, what was

the total price Ben paid?
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0

so 15% off is 149.85  which makes it 849.85 then you add sales tax which is 79.92 and your cost is 929.07


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The measure of one side of a square (s+3) inches long.which pair of expressions both represent the perimeter of this square??
ankoles [38]
Perimeter = 2w + 2l

Since its a square, the length and width are equal therefore:

2(s + 3) + 2(s + 3) = Perimeter

You can simplify this into a variety of ways:

1. 4(s + 3)
2. 2s + 6 + 2s + 6
3. 4s + 12
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PLS HELP (AGAIN) ILL MARK BRAINLIEST. I HAVE TO TURN THIS IS ASAP
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Step-by-step explanation:

A diameter spans from one end of (in this case, a circle) to the direct opposite end, going through the center-point. The radius, on the other hand, is half of a diameter, and spans only from the center-point to a point on the circle.

In this case:

1) Diameter = 18 km (given)

  Radius = 18/2 = 9 km

2) Diameter = 1 x 2 = 2 m

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3) Diameter = 17 x 2 = 34 cm

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4) Diameter = 50 mm (given)

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John has a swimming pool, in which the center of the pool to the edge is 3 meters. What is the diameter? Simply multiply 3 with 2:

3 x 2 = 6 meters

6 meters is the diameter.

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Read 2 more answers
A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under
Shkiper50 [21]

The work is equal to the line integral of \vec F over each line segment.

Parameterize the paths

  • from (0, 0, 0) to (2, 0, 0) by \vec r_1(t)=t\,\vec\imath with 0\le t\le2,
  • from (2, 0, 0) to (2, 4, 1) by \vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k with 0\le t\le1,
  • from (2, 4, 1) to (0, 4, 1) by \vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k with 0\le t\le2, and
  • from (0, 4, 1) to (0, 0, 0) by \vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k with 0\le t\le1

The work done by \vec F over each segment (call them C_1,\ldots,C_4) is

\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0

\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3

\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2

\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3

Then the total work done by \vec F over the particle's path is 46.

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4 years ago
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