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Ksju [112]
2 years ago
12

6,283.25 what place is the 2 in, in 283

Mathematics
1 answer:
Vaselesa [24]2 years ago
8 0
Its in the hundreds column
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Jada made 316 gallons of lemonade. Jada served 56 gallon to her friends. How much lemonade does Jada have left? Enter your answe
GaryK [48]

Answer:

260 gallons of lemonade

Step-by-step explanation:

Step one:

given data

We are told that Jada made 316 gallons of lemonade.

and later served 56gallons of the lemonade

Required

The remaining Lemonade

Step two

We have the total lemonade as 316

and the deducted as 56

the balance will be

= 316-56

=260 gallons of lemonade

7 0
2 years ago
What is the value of y in the equation 5x + 2y = 20, when x = 0.3?
garik1379 [7]
Y=9.25 because 5x0.3=1.5 you move constents to the right hand side and it becomes -1.5 then you do the rest and the answers is 9.25
8 0
3 years ago
Read 2 more answers
Name the types of angles shown.
PIT_PIT [208]
< ABC is a straight angle
no right angles
no complimentary angles
< ABD and < DBC are supplementary angles


7 0
3 years ago
Read 2 more answers
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
Match each fraction with its equivalent decimal number. 2/5, 7/20, 3/25, 7/10
nata0808 [166]

2/5- .4

7/20- .35

3/25-  .12

7/10- .7

5 0
3 years ago
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