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2 years ago

Sarah's brother is 12 less than twice her age. If Sarah is 16, what equation represents this situation?

Mathematics

1 answer:

dybincka [34]2 years ago

7 0

The equation that can be used to represent the ages of Sarah and his brother will be 2x - 12 = 16.

<h3>How to solve the equation</h3>

From the question given, Sarah's brother is 12 less than twice her age and Sarah is 16.

Let Sarah's age be represented by x.

Therefore, the equation to represent the situation will be:

= (2 × x) - 12 = 16

2x - 12 = 16

2x = 16 + 12.

2x = 28

x = 28/2 = 14

Sarah is 14 years.

Learn more about equations on:

brainly.com/question/13763238

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The maximum value of 12 sin 0-9 sin²0 is: -

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Answer:

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

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We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

$f(\theta) = 12sin(\theta) - 9 sin^2(\theta)$

Taking the first derivative of this with respect to $\theta$ and setting it equal to 0 lets us solve for the maximum (or minimum) value

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Eliminating $cos(\theta)$ on both sides and solving for $sin(\theta)$ gives us

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3 years ago

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Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

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First option, $5\sqrt[3]{3}$

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