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3 years ago

Please answer this for me!!

Mathematics

1 answer:

Fed [463]3 years ago

8 0

Answer: quit

Step-by-step explanation:

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Triangle xyz is similar to triangle xvw. write the congruence statements that must be true.

Lunna [17]

Answer:

∠ Y = ∠ V

∠ Z = ∠ W

$\frac{XY}{XV} =\frac{YZ}{VW} =\frac{XZ}{XW}$

Step-by-step explanation:

It is given that Δ XYZ is similar to Δ XVW.

Since corresponding angles of similar triangles are equal,

∠ X = ∠ X

∠ Y = ∠ V

∠ Z = ∠ W

Also, since corresponding sides of similar triangles are in proportionate,

$\frac{XY}{XV} =\frac{YZ}{VW} =\frac{XZ}{XW}$

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3 years ago

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75= 4(2)^x

Arlecino [84]

Answer:

x = 4.22881869...

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = − 2 + ln ( 75 ) ln ( 2 )

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3 years ago

Wendy initially has 6 hours of pop music and 3 hours of classical music in her collection. Every month onwards, the hours of pop

Rudik [331]

The correct answer is A
<span>f(x) = 6(1.09)x + 3</span>

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3 years ago

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There are 144 pieces of fruit in a box.Of the fruit in the box 1/8 are red apples and 1/4 are green apples .The rest are oranges

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There are 90 orange pieces altogether.

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Find the zero of each function and state the multiplicity of each zero. Please show all steps.

vodka [1.7K]

Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

Step-by-step explanation:

1. y=(x+3)^3

$y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3$

Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1)

$y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.$

Zeros: x=2 multiplicity 2; x=1 multiplicity 1

3. y=(2x+3)(x-1)^2

$y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.$

Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

4 0

3 years ago