The cost, ox), for a taxi ride is given by o(x) = 3x + 2.00, where x is the

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

4 0

Answer:

Since this is time and cost, we have no need for negatives, so we begin our graph at the origin (0, 0). At 0 minutes, the cost would be $2.00, so 2 is our y-intercept. For each successive minute, the cost goes up $3, so we go from (0, 2) to (1, 5), then to (2, 8), etc.n:

BRAINLIEST HACKS :))))) LOLO

You might be interested in

1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during pe

alisha [4.7K]

Answer:

a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

$X \sim Unif(a=0,b=8)$

Where a and b represent the limits of the distribution.

b) $f(x) = \frac{1}{8}= 0.125, a\leq x \leq b$

And the height for this case would be 0.125

Step-by-step explanation:

Part a

For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

$X \sim Unif(a=0,b=8)$

Where a and b represent the limits of the distribution.

Part b

For this case the density function would be given by:

$f(x) = \frac{1}{8}= 0.125, a\leq x \leq b$

And the height for this case would be 0.125

And $f(x)= 0$ for other case.

The cumulative distribution function would be given by:

$F(x) = 0, x$

$F(x) = \frac{x-a}{b-a}= \frac{x}{8}, 0\leq x < 8$

$F(x) = 1, x\geq 8$

3 0

2 years ago

What is 2. 3/6 +1/6 +1 2/3

Kaylis [27]

3/6+1/6+1 2/3
Make 1 2/3 into an improper fraction:
5/3
Give them all common denominators by multiplying both sides of 5/3 by 2:
10/6
Then the question becomes:
3/6+1/6+10/6
Now you add the numerators and the denominator stays the same:
14/6
Now you can simplify by dividing both sides by 2:
7/3
Now you can make it a mixed number:
2 1/3

Hope this helps :)

8 0

3 years ago

Read 2 more answers

IGNOR MY ANSWER I ALSO NEED TO KNOW IF IT'S OPEND OR CLOSED Graph the solution to this inequality on the number line.

Alex777 [14]

Answer:

open circle

Step-by-step explanation:

$\leq \geq = closed cirle\\ =$ open circle