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Goryan [66]
3 years ago
9

Your hotel has 200 rooms in Dallas. There is a sport event coming up, and fans either book a rooms months before or wait for the

last minute. You charge $200 per night for those who book early and $500 per night for those who book at the last minute. Demand for early booking is easy to get. The number of last minute customers is normally distributed with mean 75 and standard deviation 25. How many rooms should be set for early book customer?
Mathematics
1 answer:
dedylja [7]3 years ago
3 0

Answer:

89 rooms should be set for early book customer

Step-by-step explanation:

According to the given data we have the following:

OVERAGE(CO) = 200

SHORTAGE(CS) = 500

In order to calculate how many rooms should be set for early book customer we would have to use the following formula:

OPTIMAL BOOKING = MEAN + (Z * STDEV)

MEAN = 75

STDEV = 25

SERVICE LEVEL= CS / (CS + CO) = 500 / (500 + 200) = 0.7143

Z VALUE FOR 0.7143 = 0.57

OPTIMAL BOOKING =  75 + (0.57 * 25) = 89

89 rooms should be set for early book customer

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Use the ratio table to solve the percent problem.
rewona [7]

Answer:

30

Step-by-step explanation:

.4*75= 30

8 0
3 years ago
GIVING BRAINLIEST<br> What is the solution to the system of linear equations graphed below?
dolphi86 [110]

Answer:

The first option so (3\frac{1}{2}, -4) is the answer

<u>Skills required: Graphing Knowledge, Systems Knowledge</u>

Step-by-step explanation:

1) The solution to any system is the intersection between any 2 lines or functions. In this case, we are given two functions on a graph, and need to find the solution to them. That is the intersection.

2) We can see the intersection and see that the x-axis value for the coordinate point is around 3 1/2 (or 3.5 -- whatever you prefer), and that the y-axis value for the point is -4.

Therefore, the coordinate point is: (3\frac{1}{2}, -4) since this answer best matches the coordinate values of that point.

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Select the first option, have a nice day! :D

7 0
3 years ago
A software engineer is creating a new computer software program. She wants to make sure that the crash rate is extremely low so
Soloha48 [4]

Answer:

a) the sample size is 400

b) 95% confidence Interval for p is ( 0.0286, 0.0714 )

Step-by-step explanation:

Given the data in the question;

sample size n = 400

x = 20

p = x / n = 20 / 400 = 0.05

q = 1 - p = 1 - 0.05 = 0.95

a)

n = 400

Hence, the sample size is 400

b) 95% confidence Interval for p;

At 95% confidence interval,

significance level ∝ = 1 - 95% = 1 - 0.95 = 0.05

∝/2 = 0.05 / 2 = 0.025

so, Z critical Value ; Z_{\alpha /2 = 1.96  { from table }

So for Confidence Interval for p;

⇒ p' ± Z_{\alpha /2√( p'q' / n )

we substitute

⇒ 0.05 ± 1.96√( (0.05 × 0.95 ) / 400 )

⇒ 0.05 ± 1.96√( 0.00011875 )

⇒ 0.05 ± 1.96 × 0.010897

⇒ 0.05 ± 0.021358

⇒ ( 0.05 - 0.021358 ), ( 0.05 + 0.021358 )

⇒ ( 0.0286, 0.0714 )

Therefore, 95% confidence Interval for p is ( 0.0286, 0.0714 )

8 0
3 years ago
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malfutka [58]

Answer:3 7/10

Step-by-step explanation:

:)

8 0
3 years ago
Can someone pls help
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