What is the slope of the line

Mathematics

1 answer:

ki77a [65]2 years ago

4 0

Answer:

gradient =rise/run

Rise/run=4/4

4/4=1

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A loan of $16,840 is borrowed at 9% simple interest and is repaid with $4,167.90 interest. What is the duration of the loan?

rewona [7]

9514 1404 393

Answer:

2 3/4 years

Step-by-step explanation:

The interest is given by the formula ...

I = Prt . . . . . . principal P at annual rate r for t years

Solving for t gives ...

t = I/(Pr)

t = 4167.90/(16840×0.09) = 2.75

The duration of the loan is 2 3/4 years.

5 0

2 years ago

Please help, i will give brainliest to whos first

Wittaler [7]

Thanks with all of my heart!

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6 0

3 years ago

(01.03. 106, 1.08 HC)

zlopas [31]

Answer:

A) see attached for a graph. Range: (-∞, 7]

B) asymptotes: x = 1, y = -2, y = -1

C) (x → -∞, y → -2), (x → ∞, y → -1)

Step-by-step explanation:

A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

$\dfrac{-x^2+x+2}{x^2-3x+2}=-\dfrac{(x-2)(x+1)}{(x-2)(x-1)}=-\dfrac{x+1}{x-1}\quad x\ne 2$

This has a vertical asymptote at x=1, and a hole at x=2.

The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.

The graph is attached.

The range of the function is (-∞, 7].

As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.

The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.

The end behavior is defined by the horizontal asymptotes:

for x → -∞, y → -2

for x → ∞, y → -1