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dlinn [17]
3 years ago
12

Arrange the slope values in order from least steep to most steep

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

0 => -⅘ => 1.5 => 3 => -4 => -\frac{11}{2} (-5.5)

Step-by-step explanation:

The greater the absolute value of a slope, the steeper the slope. By absolute value, we mean the non-negative value of tthe .

To arrange the slope values, from the least steep to the steepest, ignore the negative sign in any of the slope values.

Thus, in the order from the least steep to the steepest, we have:

0 => -⅘ => 1.5 => 3 => -4 => -\frac{11}{2} (-5.5)

The greater the absolute value of the slope, the greater the vertical movement. The greater the vertical movement, the steeper the slope.

A slope value of 0 connotes a horizontal line.

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Hello,

Reminders:
$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$



$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$


$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $


n=6\\
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$ \sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\  \dfrac{i^3/8-6i}{2} $
$= \dfrac{1}{2}\sum_{i=1}^{6}  (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575


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9ff7829711a1673b799001e7d65e7199.gif
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How many acute, obtuse, and right angles are in this figure?
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Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

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Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

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