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dlinn [17]
3 years ago
12

Arrange the slope values in order from least steep to most steep

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

0 => -⅘ => 1.5 => 3 => -4 => -\frac{11}{2} (-5.5)

Step-by-step explanation:

The greater the absolute value of a slope, the steeper the slope. By absolute value, we mean the non-negative value of tthe .

To arrange the slope values, from the least steep to the steepest, ignore the negative sign in any of the slope values.

Thus, in the order from the least steep to the steepest, we have:

0 => -⅘ => 1.5 => 3 => -4 => -\frac{11}{2} (-5.5)

The greater the absolute value of the slope, the greater the vertical movement. The greater the vertical movement, the steeper the slope.

A slope value of 0 connotes a horizontal line.

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(7x-10) - (-6x-8)

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3 years ago
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Ghella [55]

Let the four consecutive integers be

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ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

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\sf4x = 18 - 6

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\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

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<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

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C.

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