Is this a simultaneous equation question?
Answer:
(x+3)/(x-4)
Step-by-step explanation:
[2x²/(x-4)(x-3)] - [x²+9/(x-4)(x-3)] =
(x²-9)/(x-4)(x-3) =
(x+3)(x-3)/(x-4)(x-3) =
x+3/x-4
<span>x^2+15=8x
</span><span>x^2-8x=-15
x^2 - 2 (x)(4) =-15
adding 16 on both sides
</span>x^2 - 2 (x)(4) +16=-15+16
x^2 - 2 (x)(4) + 4^2= 1
(x-4)^2=1
taking square root on bothsides x-4 = +-1
so x-4=1 or x-4=-1
x-5 or x=3
Answer:
Step-by-step explanation:
Since 
, then
