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zavuch27 [327]
3 years ago
12

How long will it take the United States to travel 1 kilometer

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0
It would take (100 km/hr)= 0.01 hr or 36 seconds.
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A medium-sized (4-pound) sugar pumpkin should yield around 1½ cups of mashed pumpkin. So, if a 4-pound pumpkin will yield about
Greeley [361]

Answer: 948

Step-by-step explanation:

From the question, we are informed that 4-pound pumpkin will yield about 1.5 cups of mashed pumpkin (pumpkin puree).

Therefore, the number of cups of pumpkin puree that Steve Geddes' 2,528-pound pumpkin will yield will be:

= (2528/4) × 1.5

= 632 × 1.5

= 948 cups of pumpkin puree

4 0
3 years ago
Points A(7, -5), B(-1, -2), and C(-4, 6) form triangle ABC on a coordinate plane. According to its sides, triangle ABC is a(n) _
prohojiy [21]
Isosceles Triangle, has 2 equal sides and angles. 
7 0
3 years ago
In circle C. r = 32 units.
Tamiku [17]

Answer:

1024 pi

Step-by-step explanation:

r = 32 units.

Area = pi * r^2

Area = 3.14 * 32^2

Area = 1024 * pi

Tt = pi??

7 0
3 years ago
I need Help fast asap thank you
Jobisdone [24]

Answer:

1.25

Step-by-step explanation:

Because they are equal triangles, all of their sides are equal

so, lets take one side of each triangle (4, 5)

the law:

the scale factor = the larger side ÷ the smaller side

x = 5 ÷ 4

x = 1.25

For checking:

the larger side = the smaller side × the scale factor

Y = 4 × 1.25

Y = 5

8 0
2 years ago
At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is
garik1379 [7]
Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
\\\\\\
\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}

8 0
3 years ago
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