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Mama L [17]
3 years ago
7

The area of a rectangular baking sheet is 25 square inches. The base of the sheet is 10 inches. What is the height?

Mathematics
2 answers:
padilas [110]3 years ago
5 0

Answer:

I believe is 250 in.

Step-by-step explanation:

Nady [450]3 years ago
4 0

Answer:

2 1/2

Step-by-step explanation:

take 25 and divide it by 10 giving you 5/2 but that equals 2.5 and 2.5 equals 2 1/2

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PLEASE ANSWER ASAP
kati45 [8]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1. -88 = -3(4m + 5) - (1 - 3m)​
Vadim26 [7]

Answer:

m=8

Step-by-step explanation:

-88=-3(4m+5)-(1-3m)

-88=-12m-15-(1-3m)   <- Distributive Property

-88=-12m-15-1+3m  <- Open () if there is a negative negative the symbol equals positive

-88=-9m-16    <- Simplify

0=-9m+72   <- Add 88 to both sides

9m = 72 <- Add 9m to both sides

9m = 72

/9      /9

m=8

6 0
3 years ago
Tom's stockbroker offers an investment that is compounded continuously at an annual interest rate of 3.7%. If Tom wants a return
Anettt [7]

Answer:

It'll take 38.3 years to obtain the desired return of $25,000.

Step-by-step explanation:

In order to solve a continuosly coumponded interest question we need to apply the correct formula that is given bellow:

M = C*e^(r*t)

Where M is the final value, C is the initial value, r is the interest rate and t is the time at which the money was applied. Since he wants an return of $25,000 his final value must be the sum of the initial value with the desired return. So we have:

(25000 + 8000) = 8000*e^(0.037*t)

33000 = 8000*e^(0.037*t)

e^(0.037*t) = 33000/8000

e^(0.037*t) = 4.125

ln[e^(0.037*t)] = ln(4.125)

t = ln(4.125)/(0.037)

t = 1.4171/0.037 = 38.2991

t = 38.3 years

7 0
3 years ago
Rationalize the denominator and simplify. StartFraction 5 minus StartRoot 3 EndRoot Over 4 plus 2 StartRoot 3 EndRoot EndFractio
nasty-shy [4]

Answer:

\frac{13-7\sqrt{3}}{2}

Step-by-step explanation:

We need to rationalize the denominator of = \frac{5-\sqrt{3}}{4+2\sqrt{3}}. For rationalizing we multiply the equation by \frac{4-2\sqrt{3}}{4-2\sqrt{3}}

So, solving

= \frac{5-\sqrt{3}}{4+2\sqrt{3}}*\frac{4-2\sqrt{3}}{4-2\sqrt{3}} \\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{4+2\sqrt{3}*4-2\sqrt{3}}\\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{(4)^2-(2\sqrt{3})^2}\\= \frac{5(4-2\sqrt{3})-\sqrt{3}(4-2\sqrt{3})}{16-(4*3)}\\=\frac{20-10\sqrt{3}-4\sqrt{3}+2*3}{16-12}\\=\frac{20+6-14\sqrt{3}}{4}\\=\frac{26-14\sqrt{3}}{4}\\= \frac{2(13-7\sqrt{3})}{4}\\=\frac{13-7\sqrt{3}}{2}

5 0
3 years ago
Can someone help with this
Gelneren [198K]

An equation of the form y = mx + b represents a linear function where m is the slope and b is the y-intercept. For example, y = 3x + 4 represents the linear function whose slope is 3 and whose y-intercept is 4.


Hope this helps!!! The reason why I asked which unit & lesson it is from, is because Idk if you go to k12 or not, by the pic, it looks like you do go to k12... IF you go to K12, I could tell you the answers, that's if I took that lesson... And that's if you'd tell me... Hope I make since.... Ok bye!!! :)

3 0
3 years ago
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