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2 years ago

Could you awnser this please

Mathematics

2 answers:

kobusy [5.1K]2 years ago

7 0

No, a linear function has one input for every output and this does not.

aleksklad [387]2 years ago

4 0

No it is not linear.

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You own 3/5 of the coins in a collection. What percent of the coins do you own?

Goryan [66]

60%
You divide 3/5 and then you get a decimal 0.6. Then you convert it to a percentage

4 0

2 years ago

Read 2 more answers

Which fraction is the largest 5/7 7/10 10/13 show how u worked out the answer

Ronch [10]

Answer:

$3.1/13$

Step-by-step explanation:

$1.5/7 =0.214286$

$2.7/10=0.27$

$3.1/13 =0.238462$

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3 years ago

Joe went to the store and bought 4 cans of peanuts for $7.80 .What is the constant of proportionality? (explain what you do to s

Irina-Kira [14]

Answer:

Step-by-step explanation:

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3 years ago

"Find the tangent ratio of angle Θ. <br><br> "

PSYCHO15rus [73]

Tangent Θ = opposite / adjacent

AB = short leg = opposite = 12
AC = long leg = adjacent = 5
BC = hypotenuse = 13

tangent Θ = 12/5 ⇒⇒⇒ this is in ratio form
tanΘ = 2.4 ⇒⇒⇒ this is in decimal form

8 0

3 years ago

Read 2 more answers

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$

7 0

3 years ago

Could you awnser this please​

Could you awnser this please