Applying the formula for the area of a sector and length of an arc, the value of k is calculated as: 27.
<h3>What is the Area of a Sector?</h3>
Area of a sector of a circle = ∅/360 × πr²
<h3>What is the Length of an Arc?</h3>
Length of arc = ∅/360 × 2πr
Given the following:
- Radius (r) = 9 cm
- Length of arc = 6π cm
- Area of sector = kπ cm²
Find ∅ of the sector using the formula for length of acr:
∅/360 × 2πr = 6π
Plug in the value of r
∅/360 × 2π(9) = 6π
∅/360 × 18π = 6π
Divide both sides by 18π
∅/360 = 6π/18π
∅/360 = 1/3
Multiply both sides by 360
∅ = 1/3 × 360
∅ = 120°
Find the area of the sector:
Area = ∅/360 × πr² = 120/360 × π(9²)
Area = 1/3 × π81
Area = 27π
Therefore, the value of k is 27.
Learn more about area of sector on:
brainly.com/question/22972014
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https://www.youtube.com/watch?v=5MA1eZVegg4 - click on the uploader and you'll find how to factor it.
i can't GIVE u the answers but YOU WILL LEARN IT :)
2(11 + 3x) = 64
11 + 3x =64/2
11 + 3x = 32
3x = 32 - 11
3x = 21
x = 21/3
x = 7
A.
Volume = PI x r*2 x h/3
r = radius which is shown as 8
h is the height which is shown as 63
Volume = 3.14 x 8^2 x 63/3
Volume = 3.14 x 64 x 21
Volume = 4,220.16 cubic units.
Answer:
Terminal side in 2nd Quadrant
Only sin(x) & cosec(x) are positive in 2nd Quadrant
Perpendicular=5
Base=√(13²-5²)=√(169-25)=√144=√12²=12
Hypotenuse=13
