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zmey [24]
3 years ago
11

Jackson ran 1 mile and Carlotta ran 2 3/4 miles. Tyler ran a distance halfway between Jackson and Carlotta. How far did Tyler ru

n?
Mathematics
2 answers:
laiz [17]3 years ago
6 0

I think that the answer is 3/4

masya89 [10]3 years ago
6 0
He ran 1 3/8 of a mile
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Find the domain and range of each relation. Then determine if the relation is a function. (5,0),(6,-2),(7,10),(8,-3)
leonid [27]

Answer:

Domain: 5, 6, 7, 8

Range: 0, -2, 10, -3

The relation is a function because each x-value has its own y-value.

Step-by-step explanation:

Domain: Set of all first elements in relation

Range: Set of all second elements in relation

How to determine if the relations is a function:

1. Identify the input values.

2. Identify the output values.

3. If each input value leads to only one output value, classify the relationship as a function.

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3 years ago
Solve for y in the equation <br> 5{2y+1}=4{5}y+1-15
sergejj [24]

Answer:

2/3

Step-by-step explanation:

2(y+1) =4(5)y + 1-15

2y+2=20y+1-15-2

18y=12

divide both sides by 18

y=2/3

4 0
3 years ago
What is the equation of the line that passes through the point (5, 4) and has a slope<br> of 4/5
nataly862011 [7]

Answer:

Every point on a horizontal line has the same y-value. Use the y-value of the point to find the equation of the horizontal line.

y=4

8 0
3 years ago
D.) is 13/5 it got cut off<br> HELP NEEDED<br> [10 points up!]
vodomira [7]

It would be A. You can find this out by using SOH CAH TOA,

SOH means sin= opposite/hypotenuse

CAH mean cos= adjacent/hypotenuse

TOA means tangent= opposite/adjacent

You would use CAH since you are trying to find cos∠C

You would have cos∠C=10/26.

26 is the hypotenuse since it is opposite the right angle and is the biggest side.

10 is the adjacent since it is right next to C

You would simplify this down to 5/13 by dividing by 2.

This gives you A.

5 0
3 years ago
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Which best describes your ability to use graphs to model relationships?
alekssr [168]

Answer:

My answer is C

Step-by-step explanation:

I know how to use a graph kind of but I have trouble of calculating and stuff like that.

3 0
2 years ago
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