Answer:
X= 50°
Y= 70°
Z= 30°
BDE= 30°
2BDE= 60°
Step-by-step explanation:
(2x -70 )+z+(2x+20)=180...(sum of angle on a straight line)
2x -70 = BDE... alternate angles
Y + (2x-70)+(50+x-20) = 180...(sum of angles in a triangle)
X-20 = z ... alternate and opposite angles
(2x -70 )+z+(2x-+20)=180
2x-70 + x-20 +2x +20= 180
5x -70= 180
5x = 250
X= 50°
X-20 = z
50-20= z
30° = z
2x -70 = BDE
2(50) -70 = BDE
100-70 = BDE
30°= BDE
Y + (2x-70)+(50+x-20)
Y + 100-70 +50 +50 -20 = 180
Y + 200-90=180
Y= 70°
2BDE = 2*30
2BDE= 60°
Answer: understand , strategize and implement
Hoped it helped , if it didn’t I apologize
Good luck
answer:
Step-by-step explanation:
On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).
now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is , where (p,q) is the turning point. now we substitute the turning point
, now we will substitute the other point on the graph or on the function that we found which is (3.15, 0) then solve for a.
0 = a(3.15 - 0.76)^2 + 57
-57 =a(2.39)^2
-57 = a(5.7121)
-57/5.7121 =a
-9.9788169 = a then we substitute a to get the quadratic equation therefore f is