Answer:
18.1 cm
Step-by-step explanation:
AD segment breakup: 11=4+7
Pythagorean Theorem:
7^2+b^2=16^2
49+b^2=256
x^2=207
b=sqrt(207)
b=3sqrt(23)
Pythagorean Theorem:
11^2+3sqrt(23)^2=c^2
121+207=c^2
328=c^2
18.11=c
So the length of AC is around 18.1 cm
(X+4)(X-4) is the LCD because you just have to look at the denominators and see what factors or values are not already part of your LCD.
Answer:
The answer is 675.75 square Inches
Step-by-step explanation:
<h3><u>Given</u>;</h3>
<h3>
<u>To </u><u>Find</u>;</h3>
<h3>
<u>Formula</u>;</h3>
Now,
Radius (r) = diameter ÷ 2
r = 14/2 in.
r = 7 in.
Now,
A = 4πr²
A = 4 × 22/7 × (7)² in.
A = 4 × 22 × 7 in.
A = 615.75 square in.
Thus, The area of the beach ball with a diameter of 14 in. is 615.75 square in.