Explanation:
Multiply the given moles times the molar mass of neon, 20.180 g/mol (periodic table).
In deserts, wind often causes weathering by blowing sand and other material against cliffs and large rocks. This wears them down and creates more bits of sand and dust. Over time, the rock is scraped and polished away. ... When a gust of wind blows, it picks up sand and other bits of material.
<u>Given:</u>
Mass of Ag = 1.67 g
Mass of Cl = 2.21 g
Heat evolved = 1.96 kJ
<u>To determine:</u>
The enthalpy of formation of AgCl(s)
<u>Explanation:</u>
The reaction is:
2Ag(s) + Cl2(g) → 2AgCl(s)
Calculate the moles of Ag and Cl from the given masses
Atomic mass of Ag = 108 g/mol
# moles of Ag = 1.67/108 = 0.0155 moles
Atomic mass of Cl = 35 g/mol
# moles of Cl = 2.21/35 = 0.0631 moles
Since moles of Ag << moles of Cl, silver is the limiting reagent.
Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles
Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol
Ans: Formation enthalpy = 126.5 kJ/mol
Answer:
The graph of the relationship of temperature one volume is a graphical representation of Charles law.
Explanation:
The graph shows the relationship between volume vs temperature plotted at constant pressure for a fixed amount of gas. As can be observed from the graph, the volume increases with an increase in the temperature, and vice versa. Thus, volume is directly proportional to temperature at a constant pressure, which is the statement of Charles's law.
Volume is plotted on the y- axis, and temperature is on x-axis. The graph is a straight line with a positive slope passing the origin. The equation of the line is V = kT, which is the equation of Charles's law. The slope of the line is k. As temperature approaches zero kelvin, volume also approaches zero.
Real gases do not obey Charles's law at low temperatures. As temperature approaches absolute zero (0 K), the real gases start deviating significantly from Charles's law.
mass percent concentration = 15.7 %
molar concentration of glucose solution 1.03 M
Explanation:
To calculate the mass percent concentration of the solution we use the following formula:
concentration = (solute mass / solution mass) × 100
solute mass = 60.5 g
solution mass = solute mass + water mass
solution mass = 60.5 + 325 = 385.5 g (I used the assumption that the solution have a density of 1 g/mL)
concentration = (60.5 / 385.5) × 100 = 15.7 %
Now to calculate the molar concentration (molarity) of the solution we use the following formula:
molar concentration = number of moles / volume (L)
number of moles = mass / molecular weight
number of moles of glucose = 60.5 / 180 = 0.336 moles
molar concentration of glucose solution = 0.336 / 0.325 = 1.03 M
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molarity
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