If all three metals were exposed to extremely high temperatures, which would be the last to melt? (copper, gold, mercury)
2 answers:
You might be interested in
The final temperature of the mixture : 21.1° C
<h3>Further explanation </h3>The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released
Q in(gained) = Q out(lost)
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Q ethanol=Q water
mass ethanol=
mass water =
then the heat transfer :
The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.
The volume of water is .
Since, 1 gal= 3785.41 mL
Thus,
Density of water is 1 g/mL thus, mass of water will be .
Since, 1 grams of chlorine → grams of water.
1 g of water → g of chlorine and,
of water →86.6 g of chlorine
Since, the solution is 9% chlorine by mass, the volume of solution will be:
Thus, volume of chlorine solution is 9.62\times 10^{2} mL.