What is the oxidation number of Chlorine in NaClO4?
2 answers:
<u>Answer:</u> Oxidation state of chlorine in the given compound is +7.
<u>Explanation:</u>
Oxidation state is defined as the number which is assigned to the element when it gains or loose electrons. If the element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.
We take the oxidation state of chlorine atom be 'x'.
Oxidation state of sodium atom = +1
Oxidation state of oxygen atom = -2
Evaluating the oxidation state of chlorine atom:
Hence, the oxidation state of chlorine in the given compound is +7.
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Answer:
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- <u><em>Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.</em></u>
Explanation:
Charle's Law for ideal gases states that, at constant pressure, the <em>temperature</em> and the <em>volume</em> of a sample of gas are protortional.
That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.
When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left 273.15ºC.
Meaning that the Volume at 273.15ºC is zero.
You cannot reach such low temperatures in an experiment, and also, volume zero is not real.
Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.
Subject to the experimental errors, and the fact that the real gases are not ideal, the temperature that you read on the x-axis is the minimum possible temperature (<em>absolute zero</em>) as the minimum possible volume is zero.