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Simora [160]
3 years ago
6

I have to put 20 characters so here we are. Pls help tho.

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0

ABC is an isosceles triangle so AB =  BC

Plug in

x + 4 = 3x - 8

-2x = - 12

x = 6

AC = x = 6

Answer

6 units

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1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
2 years ago
Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point
a_sh-v [17]
A line parallel to y = 0.6x + 3 will be of the form:

y = 0.6x + k

where k is a constant.

It passes through (-3,-5)

Thus,

y = 0.6x + k \\ \\ -5 = 0.6 \times (-3) + k \\ \\ -5 = -1.8 + k \\ \\k = -5 + 1.8 \\ \\ k = -3.2

\textbf{The equation is \: \: y = 0.6x - 3.2}
3 0
3 years ago
Which expression has a value of 66? A. (16 ÷ 3.2) × 2 + 0.2 × (8 + 82) B. [(16 ÷ 3.2) × (2 + 0.2)] × 8 + 82 C. 16 ÷ [(3.2 × 2) +
Setler [38]

Answer: none

Step-by-step explanation:

(A)

(16÷32/10) ×2 + 0.2×(90)

Using bodmas principle ; solve bracket

(16×10/32)×2 + (2/10×90)

10+18 =28

(B)

{(16÷32/10) × (2+2/10)} ×90

Open brackets

{(16×10/32) × (22/10)} ×90

(5×11/5) ×90

11×90 = 990

(C)

16÷{(32/10×2) + (2/10×8)} +82

Open brackets, solve division first, dolled by addition

16÷(32/5 + 8/5) +82

16÷(40/5) +82

16÷8 +82

2+82= 84

(D)

[16÷(32/10 ×2) + 0.2× (90)]

16÷ (32/5) + 2/10 ×90

Solve division

16×5/32 + 18

5/2 + 18

L.c.m of denominator (2&1) =2

(5+36) / 2 = 41/2

=20.5

8 0
3 years ago
On monday 2/3 of the team practiced, Tuesday 7/8, wendsday 1/2 and Thursday 3/4 which is the most
dimulka [17.4K]
 i believe its tuesday 7/8


6 0
3 years ago
Read 2 more answers
If a sprinkler Waters 1/20 of a lawn in 1/5 of an hour, how much time will it take to water the entire lawn?
loris [4]
4hrs, I think, because 20 divided by 5 is 4.
6 0
3 years ago
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