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guajiro [1.7K]
3 years ago
7

6. _______ is a neutral solution. A. Blood B. Salt water C. Pure water D. Milk E. All of the Above

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
4 0

The answer is option E. All of the above

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10 atoms of Hydrogen and 5<br> atoms of Oxygen would make<br> molecules <br> of water.
steposvetlana [31]

Answer:

No, it won't. Because water is made up of two atoms of hydrogen and an atom of oxygen (the composition of water).So now do you understand? Text me if you do/don't for more explanation. Thanks for asking

7 0
3 years ago
An ionic compound has a very negative heat of solution in water. Would you expect it to be soluble or insoluble in water?.
ddd [48]

Answer:

It will be Insolube in water

8 0
2 years ago
State the reason that soft drinks is a mixture and water is a compound?
Yuri [45]
Carbonated drinks are a mixture of many compounds such as glucose(sugar) and others, while water is simply its own molecule.
7 0
3 years ago
Read 2 more answers
Aluminum and oxygen react according to the following equation: 4Al + 3O2 -&gt; 2Al2O3 In a certain experiment, 4.6g Al was react
stiv31 [10]

Answer:

Percent yield: 78.2%

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

(Actual yield (6.8g) / Theoretical yield) × 100

Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:

4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>

Thus, Percent yield is:

(6.8g / 8.7g) × 100 =

<h3>78.2% </h3>
8 0
3 years ago
a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g
leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

Solution :

By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

Therefore , percentage of Na by mass in NaBr will be same for every amount .

Percentage of Na in 9.77 g NaBr is 22.34 % too .

Gram of Na = 9.77\times \dfrac{22.34}{100}=2.18\ g .

Hence , this is the required solution .

7 0
3 years ago
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