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RUDIKE [14]
3 years ago
14

Please help me thanks so much?!?!

Chemistry
2 answers:
fgiga [73]3 years ago
7 0

Answer:

The answer to your question is when the size, shape, or state of matter changes.

Explanation:

Change that does not undergo in the chemical composition.

AVprozaik [17]3 years ago
3 0

Answer:

D.

Explanation:

I did this question in school and got it right.

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Read 2 more answers
1.- ¿Cuál es la densidad del corcho, si un cubo que mide 1.50 cm de lado tiene la masa de 1.00 g?
Brrunno [24]

Answer: 2.50

Explanation:

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3 years ago
I don't get this? Please help!
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Suppose that the mixture in problem 4 is at 15 OC, where the pure vapor pressures are 12.5 mmHg for water and 32.1 mmHg for etha
EleoNora [17]

Answer:

Explanation:

Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.

Using Raoult's Law:

P_A = (P_o)_A*X_A

For water:

(P)w = P_o \times \text{mole fraction of water}

where P_o of water = 12.5 mmHg

Then, the vapor pressure of water:

(P)w = 12.5 \ mmHg \times \text{mole fraction of water}

For ethanol:

P_E = P_o \times \text {mole fraction of ethanol}

and the P_o of ethanol = 32.1 mmHg

Then, the vapor pressure of ethanol:

P_E = 32.1 \ mmHg \times \text {mole fraction of ethanol}

The total vapor pressure T_P = P_W + P_E

The total vapor pressure = (12.5 \ mmHg \times \text{mole fraction of water}) + (32.1 \ mmHg \times \text {mole fraction of ethanol})

3 0
3 years ago
vanadium has an atomic mass of 50.9415 amu. it has two common isotopes.one isotopes has a mass of 50.9440 amu and a relative abu
Kaylis [27]

Explanation:

Average atomic mass of the  vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

The atomic mass of isotope (II) of vanadium is 49.944 amu.

5 0
3 years ago
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