Answer:
Judging from the wording of he question, you mean units. If that is indeed the case, the answer is g/Mol (grams per mol)
Let me know if my interpretation is incorrect and please tell me what you are actually trying to find.
Answer:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001 
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13 
From ideal gas equation P V = m RT
⇒ P = 
Put all the values in above formula we get
⇒ P =
× 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
Theoretical Yield is an Ideal yield with 100 % conversion of reactant to product. It is in fact a paper work.
While,
Actual Yield is the yield which is obtained experimentally. It is always less than theoretical yield because it is not possible to have 100% conversion of reactants into products. Even some amount of product is lost while handling it during the process.
Percentage Yield is Calculated as,
%age Yield = Actual Yield / Theoretical Yield × 100
Data Given:
Actual Yield = 0.104 g
Theoretical Yield = 0.110 g
Putting Values,
%age Yield = 0.104 g / 0.110 g × 100
%age Yield = 94.54 %
Answer:
Explanation:
A chemical formula can be defined as a notation that is used to show which element and how many is contained in a chemical compound.
Also, in chemistry, the sum of charges of the anion and the cation of any ionic compound is always equal to zero.
A chemical equation is considered to be balanced when the amount of reactants on the left is equal to the amount of products on the right.
Therefore;
[2]FeBr3 + [3]Na2S → [1]Fe2S3 + [6]NaBr
In the above chemical equation, we will balance the reactants in the chemical equation with the smallest coefficients possible;
Two (2) moles of Iron (III) Bromide reacts with two (2) moles of Sodium Sulfide to form Iron (III) Sulfide and Sodium Bromide.
<u>Answer:</u> The amount of CO that is occupied in the room is 
<u>Explanation:</u>
We are given:
Concentration of CO =
by volume
This means that
of CO is present in 1 L of blood
To calculate the volume of cuboid, we use the equation:

where,
V = volume of cuboid
l = length of cuboid = 10.99 m
b = breadth of cuboid = 18.97 m
h = height of cuboid = 11.89 m

Converting this into liters, by using conversion factor:

So, 
Applying unitary method:
In 1 L of blood, the amount of CO present is 
So, in
of blood, the amount of CO present will be = 
Hence, the amount of CO that is occupied in the room is 