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2 years ago

What is the density of a solid with a mass of 75g and a volume of 5 cm^3?

Chemistry

1 answer:

beks73 [17]2 years ago

7 0

Answer: 15 g/cm^3

Explanation: formula for density is d= m/v where d is the density, m is the mass and v is the volume. If we plug in the values from the question, we get d= 75/ 5. 75 divided by 5 is 15 so the density is 15 grams per cubic centimetre.

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A solution may contain Ag+, Pb2+, and/or Hg22+. A white precipitate forms when 6 M HCl is added. The precipitate is partially so

omeli [17]

Answer:

All three are present

Explanation:

Addition of 6 M HCl would form precipitates of all the three cations, since the chlorides of these cations are insoluble: $AgCl (s), PbCl_2 (s), Hg_2Cl_2 (s)$ .

Firstly, the solid produced is partially soluble in hot water. Remember that out of all the three solids, lead(II) choride is the most soluble. It would easily completely dissolve in hot water. This is how we separate it from the remaining precipitate. Therefore, we know that we have lead(II) cations present, as the two remaining chlorides are insoluble even at high temperatures.
Secondly, addition of liquid ammonia would form a precipitate with silver: $AgCl (s) + 2 NH_3 (aq) + H_2O (l)\rightarrow [Ag(NH_3)_2]OH (s) + HCl (aq)$ ; Silver hydroxide at higher temperatures decomposes into black silver oxide: $2 [Ag(NH_3)_2]OH (s)\rightarrow Ag_2O (s) + H_2O (l) + 4 NH_3 (g)$ .
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3 0

3 years ago

Realice las siguientes conversiones: a) 72°F a °C, b) 213.8°C a °F, c)180°C a K, d) 315K a °F, e) 1750°F a K, f) 0K a °F.

bonufazy [111]

Answer:

a) 72 °F= 22.22 °C

b) 213.8 °C= 416.84°F

c) 180 °C= 453.15 °K

d) 315 °K= 107.33 °F

e) 1750 °F= 1227.594 °K

f) 0 °K= -459.67 °F

Explanation:

Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:

Fahrenheit a Celsius: $C=\frac{F-32}{1.8}$

Celsius a Fahrenheit: °F= °C*1.8 + 32
Celsius a Kelvin: °K= °C + 273.15
Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
Fahrenheit a Kelvin: $K=\frac{F-32}{1.8} + 273.15$

Entonces se obtiene:

a) 72 °F= $\frac{72-32}{1.8}$ =22.22 °C

b) 213.8 °C= 213.8*1.8 + 32= 416.84°F

c) 180 °C= 180°C + 273.15= 453.15 °K

d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F

e) 1750 °F= $\frac{1750-32}{1.8} + 273.15$ = 1227.594 °K

f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F

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2 years ago

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Answer:

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Answer:

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3 years ago

What is the density of a solid with a mass of 75g and a volume of 5 cm^3?​

What is the density of a solid with a mass of 75g and a volume of 5 cm^3?