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Ahat [919]
3 years ago
8

What is the highest unit price per kazoo if 25 are $10, 50 are $18.50 and 80 are $27.20

Mathematics
1 answer:
mafiozo [28]3 years ago
5 0
The answer I got 0.4

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Solve the system using substitution.
valkas [14]

Good evening ,

Answer:

<h2>(3,15)</h2>

Step-by-step explanation:

y=5x then

4x-y= -3 ⇌ 4x-5x= -3 ⇌ -x= -3 ⇌ x=3

and since y=5x then y=5×3=15.

______________________________

:)

5 0
3 years ago
Find the surface area of composite figure. Please help
Ivan

Answer:

The surface area of the composite figure is 410\ m^{2}

Step-by-step explanation:

we know that

The surface area of the composite figure is equal to the surface area of the rectangular prism of the bottom plus the lateral area o the rectangular prism of the top

so

Step 1

Find the surface area of the rectangular prism of the bottom

The surface area is equal to

SA=2B+Ph

Find the area of the base B

B=10*10=100\ m^{2}

P=4*10=40\ m

h=3\ m

substitute

SA=2(100)+40(3)=320\ m^{2}

Step 2

Find the lateral area of the rectangular prism of the top

The lateral area is equal to

LA=Ph

P=2*(4+5)=18\ m

h=5\ m

substitute

LA=18(5)=90\ m^{2}

Step 3

Find the surface area of the composite figure

320\ m^{2}+90\ m^{2}=410\ m^{2}

8 0
3 years ago
Four friends played a game. At the end of the game, their scores were -8, -2, 1, and -3. What is the lowest score?
kiruha [24]

Answer:

the lowest scoreis -3

Step-by-step explanation:

the lowest score is -3

4 0
3 years ago
Plis help me on how much you can thank you first to reply gets brainless
victus00 [196]

Answer:

yeet

Step-by-step explanation:

yeet yeet yeet yeet yeet yeet yeet yeet yeet eet yett yeet yeet yeet yeet yeet yeet yeet yeet yeety

6 0
3 years ago
Which one is a better buy A. a bag of 6 oranges for $5.88 or a bag of 10 oranges for $9.20 Show and explain why.​
Dmitriy789 [7]

Answer:

a bag of 10 oranges for $9.20

Step-by-step explanation:

5.88 divided by 6= 0.98 and 9.20 divided by 10=0.92 so $0.92 per orange is cheaper than $0.98 per orange.

8 0
3 years ago
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