The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2.Three scores extracted from the te
st 148,102,152,what is the average of the extracted scores that are extreme values(outlier).
1 answer:
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: mark obtained in an aptitude test by a candidate.
This variable has a mean μ= 128.5 and standard deviation σ= 8.2
You have the data of three scores extracted from the pool of aptitude tests taken.
148, 102, 152
The average is calculated as X[bar]= Σx/n= (148+102+152)/3= 134
I hope this helps!
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