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timurjin [86]
3 years ago
15

Wayne is 12 mi due north of Jefferson, and Oakland is due west of Jefferson. Wayne is 28 mi from Oakland. How far apart are Jeff

erson and Oakland? Round your answer to the nearest tenth of a mile. Do not include units.
Mathematics
1 answer:
bija089 [108]3 years ago
3 0
The anwer is 233,000 and that is the anwer so i need a thank you
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Hich of the following are the coordinates of the vertex of y = x2 − 10x + 2?
ANEK [815]
The vertex is in essence the turning point of the parabola y = x²<span> − 10x + 2

the x coordinate of the turning point = </span>- \frac{b}{2a}
                                                         = - \frac{-(10)}{2(1)}
                                                         =  5

when x = 5, y = (5)² - 10(5) + 2
                      = -23

Thus coordinate or vertex is ( 5, -23)

6 0
3 years ago
What is the point-slope form of a line with slope 3 that contains the point (2,1)?
Serjik [45]

Answer:

A) y-1=3(x-2)

Step-by-step explanation:

Point-slope formula.

y-y_1=m(x-x_1)

Given.

Slope (m) = 3

Points (x, y) = (2, 1)

8 0
3 years ago
1 HOUR TIME LIMIT
irina1246 [14]

Answer:

Your answer is 1500 foot pounds.

I hope this helps!

Step-by-step explanation:

Edg 2020

3 0
2 years ago
Read 2 more answers
Which linear inequality is represented by the graph?
Dovator [93]

Answer:

The answer to your question is   the second choice (y ≥ 1/3x - 1)

Step-by-step explanation:

Process

1.- Find two points of the graph

A (0, -1)

B (3, 0)

2.- Find the slope

m = (0 + 1)/(3 - 0)

m = 1/3

3.- Find the equation of the line

     y - y1 = m(x - x1)

     y + 1 = 1/3(x - 0)

     y + 1 = 1/3x

     y = 1/3x - 1

4.- Find the equation of the inequality

      We need the upper part of the line so the inequality must be

       y ≥ 1/3x - 1

3 0
2 years ago
I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
Read 2 more answers
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