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timurjin [86]
3 years ago
15

Wayne is 12 mi due north of Jefferson, and Oakland is due west of Jefferson. Wayne is 28 mi from Oakland. How far apart are Jeff

erson and Oakland? Round your answer to the nearest tenth of a mile. Do not include units.
Mathematics
1 answer:
bija089 [108]3 years ago
3 0
The anwer is 233,000 and that is the anwer so i need a thank you
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Solve the rational equation: 7 - 2/x = 4 + 10/x
vlabodo [156]

Answer:

7 - 2 / x = 4 + 10 / x

or , 7 - 4 = 10 / x + 2 / x

or , 3 = 12 / x

or , x = 12 / 3

Therefore , x = 4

7 0
3 years ago
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H(a) = a^2 + 3a; Find h(-10)
Colt1911 [192]
H(-10)=70
because when you input -10 in for each a, it will equal 70
6 0
2 years ago
Can someone help me with this?
forsale [732]

Answer:

36 ft.

Step-by-step explanation:

The given perimeter of triangle EDF is 12, in which the hypotenuse is 5. This means that it is a 3-4-5 triangle, meaning that ED = 3, DF = 4, EF = 5.

It is given that BC (the other triangle's hypotenuse) is 15. This means that the left triangle is to the scale factor of 3 of triangle EDF. Therefore, multiply 3 to all sides measurements, and then add all the sides to get the perimeter.

Hypotenuse: 5 x 3 = 15

Leg 1: 4 x 3 = 12

Leg 2: 3 x 3 = 9

Perimeter: 15 + 12 + 9 = 36

36 ft. is your answer.

8 0
2 years ago
4. The Emerson First National Bank is lending you money to buy a new car. The loan agreement will probably state
BlackZzzverrR [31]

Answer:

D. liability​

Step-by-step explanation:

The Emerson First National Bank is lending you money to buy a new car.

Before an agreement will be reached for any Organization to lend someone money there have to be something like a collateral.

The agreement will in it's document state that there must be a form of a reliability to hold on, such that if something's happen to the car, or you don't meet the paying up time, or something happens to you,they will see something to hold on.

5 0
2 years ago
Let the function f be continuous and differentiable for all x. Suppose you are given that f(−1)=−3, and that f'(x) for all value
Monica [59]

Answer:

Step-by-step explanation:

By MVT,

f'(c) = \frac{f(5)-f(-1)}{5-1}

4f'(c)= f(5) + 3\rightarrow f(5) = 4f'(c) - 3

Moreover, f'(x)\leq 4~~~~~~ \forall x,

f(5) \leq 16 - 3 =13

Hence the largest possible value of f(5) is 13

8 0
3 years ago
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