First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Answer:
200 - 200
-147 - 53
90 - 143
-229 - -86
86 - 0
Step-by-step explanation: im not sure on the last two but i tried?
Answer: See explanation
Step-by-step explanation:
Here is the complete question:
A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.
A. Students: 72
Minimum of chaperones: 9
B. Students: 16
Minimum of chaperones: 2
C. Students: 60
Minimum of chaperones: 6
D. Students: 45
Minimum of chaperones: 5
E. Students: 40
Minimum of chaperones: 8
Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.
We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:
Students: 72
Minimum of chaperones: 9
This will be: 72/9 = 8
Therefore, this is correct.
B. Students: 16
Minimum of chaperones: 2
This will be: 16/2 = 8
This is correct
C. Students: 60
Minimum of chaperones: 6
This will be: = 60/6 = 10.
Therefore, this is wrong
D. Students: 45
Minimum of chaperones: 5
This will be 45/5 = 9
Therefore, this is wrong.
E. Students: 40
Minimum of chaperones: 8
This will be: 40/5 = 8.
Therefore, this is wrong.
Therefore, options A and B are correct.
Answer:
Wouldn't the third term be 21?
This is the isosceles right triangle, the diagonal of a square, the thing that so upset the Pythagoreans. The two sides and diagonal of a square are in ratio 
so we get
We could have also gotten this using Trig:
Or by recognizing u=v because remaining angle is 45 so this must be isosceles so
