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BlackZzzverrR [31]
3 years ago
15

Two lines that are perpendicular intersect to make 90 degree angles that are classified

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0
Wouldn’t it be a right angle, I’m pretty sure it would be a right angle. Only perpendicular lines can intersect and create one.
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How do you do C and B
Hoochie [10]
"the argument" of a function, is simply "the expression being evaluated by that function".

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b)\qquad f(2x-1)\impliedby \stackrel{function}{f(\qquad )}\qquad \stackrel{argument}{2x-1}
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c)\qquad \sqrt{x^2+4}\qquad \stackrel{function}{\sqrt{\qquad }}\qquad \stackrel{argument}{x^2+4}
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4 0
2 years ago
1. In 2011, Molly and Jerry both went to
True [87]

Answer:

2017

Step-by-step explanation:

Molly goes every 2 years

Jerry goes every 3 years

LCM(2,3) = 2 x 3 = 6

2011 + 6 = 2017

The answer is 2017

6 0
2 years ago
Estimate the answer for 753 - 289
denis23 [38]

Answer:

464 or 460

Step-by-step explanation:

464 is the actual answer but if you were to estimate I would go with 460

8 0
2 years ago
A survey is conducted to find out whether people in metropolitan areas obtain their news from television (Event T), an newspaper
MrMuchimi

Answer:

e) P ( R' | T ) = 0.62857

f)  P ( T' | N ) = 0.32258

g)  P ( R' | N ) = 0.70968

h) P ( T' | N&R ) = 5/6

Step-by-step explanation:

Given:

- The probability of Television as news source P ( T ) = 0.7

- The probability of Newspaper as news source P ( N ) = 0.62

- The probability of Radio as news source P ( R ) = 0.46

- The probability of Television & Newspaper as news source P (T&N) = 0.42

- The probability of Television & Radio as news source P (T&R) = 0.26

- The probability of Radio & Newspaper as news source P (R&N) = 0.18

- The probability of all 3 as news source P ( T & R & N ) = 0.03

Find:

Given that TV is a news source, what is the probability that radio is not a news source?

Given that newspaper is a news source, what is the probability that TV is not a news source?

Given that newspaper is a news source, what is the probability that radio is not a news source?

Given that both newspaper and radio are news sources, what is the probability that TV is not a news source?

Solution:

- We will first compute the individual probability of each event occurring alone.

   P (Television is the only news source) = P(T) - P(T&R) - P(T&N) + P(T&N&R)

   P ( Only Television ) = P ( only T ) = 0.7 - 0.42 - 0.26 + 0.03 = 0.05

   P (Newspaper is the only news source) = P(N)-P(N&R)-P(T&N)+P(T&N&R)

   P ( Only Newspaper ) = P ( only N ) = 0.62 - 0.18 - 0.42 + 0.03 = 0.05

   P (Radio is the only news source) = P(R) - P(T&R) - P(N&R) + P(T&N&R)

   P ( Only Radio ) = P ( only R ) = 0.46 - 0.26 - 0.18 + 0.03 = 0.05

- Now for part e)

   We are asked for a conditional probability of the form as follows:

            P ( R' | T ) = P ( R' & T ) / P ( T )

   First compute the probability that next news source is not Radio provided it is already a source of TV.                              

            P ( R' & T ) =  P( only T ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | T ) = 0.44 / 0.7

            P ( R' | T ) = 0.62857

- Now for part f)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N ) = P ( T' & N ) / P ( N )

   First compute the probability that next news source is not TV provided it is already a source of Newspaper.                              

            P ( T' & N ) =  P( only N ) + P ( only R & N ) = 0.05 + 0.18 - 0.03 = 0.2

Hence,

           P ( T' | N ) = 0.2 / 0.62

           P ( T' | N ) = 0.32258

- Now for part g)

   We are asked for a conditional probability of the form as follows:

            P ( R' | N ) = P ( R' & N ) / P ( N )

   First compute the probability that next news source is not Radio provided it is already a source of Newspaper.                              

            P ( R' & N ) =  P( only N ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | N ) = 0.44 / 0.62

            P ( R' | N ) = 0.70968

- Now for part h)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N&R ) = P ( T' & N & R) / P ( N & R )

   First compute the probability that next news source is not TV provided it is already a source of both radio and Newspaper.                              

            P ( T' & N & R) = P ( only N & R ) = 0.18 - 0.03 = 0.15

Hence,

            P ( T' | N&R ) = 0.15 / 0.18

            P ( T' | N&R ) = 5/6

6 0
3 years ago
Pls help!!!!!!!! Will give brainliest!!!!!!!!!!!
prohojiy [21]
Okay so lets look at the equation given
a ^{2} + {b}^{2} = {c}^{2}
this is the Pythagorean theorem, this equation holds true to all right angle triangles.

for the "a" and "b" terms must be the two shortest lengths and "c" must be the longest length.
why? because "c" represents the hypotenuse in this theorem and the hypotenuse is by definition the longest side of a right triangle.

(side note: always draw a picture, it helps a lot if you doodle a bit to get an idea of what you are working with)

we are given three lengths : 3 , 4, and 5 (im ignoring the measurements for now)

we can look at it two ways with a picture and through algebra

try to draw a right triangle with the given info. you'll see there are only two cases were this is possible the picture above is one case where this is not possible

now we can look at this algebraically
a = 3 \\ b = 4 \\ c = 5
(but "a" and "b" can swap lengths)

now with the Pythagorean theorem we can see how this plays out
{a}^{2} + {b}^{2} = {c}^{2} \\ {3 }^{2} + {4}^{2} = {5 }^{2} \\ 9 + 16 = 25 \\ 25 = 25
and heres with "a" and "b" lengths swapped
{4}^{2} + {3}^{2} = {5}^{2} \\ 16 + 9 = 25 \\ 25 = 25
now here's a case when we let 5 , our longest length , become a leg and let one our shorter lengths take the place of "c"

a = 5 \\ b = 3 \\ c = 4 \\ {5}^{2} + {3}^{2} = {4}^{2} \\ 25 + 9 = 16 \\ 34 = 16 \:
obviously 34 does not equal 16

hope this helped you out

4 0
3 years ago
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