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Lena [83]
2 years ago
5

Help this is due today-

Mathematics
2 answers:
WITCHER [35]2 years ago
8 0
Because y =9 The volume = 9 * 9 * 9 = 729
ludmilkaskok [199]2 years ago
7 0

Answer:

729

hopefully I will be there is no

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In circle F with m \angle EFG= 122m∠EFG=122 and EF=16EF=16 units, find the length of arc EG. Round to the nearest hundredth.
kow [346]

Given:

In circle F, m\angle EFG=122^\circ,\ EF=16 units.

To find:

The length of arc EG.

Solution:

It is given that, m\angle EFG=122^\circ,\ EF=16 units. It means the central angle of arc EG is 122 degrees and the radius of the circle F is 16 units.

Formula for arc length is:

s=2\pi r\times \dfrac{\theta}{360^\circ }

Where, r is the radius and \theta is the central angle in degrees.

Putting r=16,\ \theta=122^\circ,\ \pi=3.14, we get

s=2(3.14)(16)\times \dfrac{122^\circ}{360^\circ }

s=100.48\times \dfrac{61}{180}

s=34.0515556

s\approx 34.05

Therefore, the length of arc EG is 34.05 units.

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3 years ago
Root 54 to the nearest tenth
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Alenkinab [10]
X = -1.   8 = 4x+12
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Graph and label each quadrilateral. 14,16,18.
slava [35]

Answer:

We could see the graph of all of the three questions of the quadrilaterals as is attached with the answer.

Ques 14)

The vertices of quadrilateral is given as:

W(-1,1),X(0,2),Y(1,2),Z(0,-2)

Ques 15)

The vertices of the quadrilateral is given as:

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Ques 18)

The vertices of the quadrilateral are given as:

E(-3,1), F(-7,-3) ,G(6,-3) and H(2,1)




8 0
3 years ago
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