Parallel lines r and s are cut by two transversals, parallel lines t and u. Lines r and s are crossed by lines t and u to form 1
2 answers:
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Answer:
(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.
(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.
(c) The probability that exactly 1 of the next three vehicles passes is 0.189.
(d) The probability that at most 1 of the next three vehicles passes is 0.216.
(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.
Step-by-step explanation:
Let <em>X</em> = number of vehicles that pass the inspection.
The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.
(a)
Compute the probability that all the next three vehicles inspected pass the inspection as follows:
P (All 3 vehicles pass) = [P (X)]³
Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.
(b)
Compute the probability that at least 1 of the next three vehicles inspected fail as follows:
P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)
Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.
(c)
Compute the probability that exactly 1 of the next three vehicles passes as follows:
P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)
= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)
+ P (Only 3rd vehicle passes)
Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.
(d)
Compute the probability that at most 1 of the next three vehicles passes as follows:
P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)
+ P (0 vehicles passes)
Thus, the probability that at most 1 of the next three vehicles passes is 0.216.
(e)
Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.
Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:
Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.
Answer:
Therefore, the approximate monthly payment is $548.85
Step-by-step explanation:
The amount of student loans Erica currently has = $34,006.00
The duration over which Erica is to pay back the loan = 7 years
The annual interest rate for the loan = 9.1%
Therefore, we have the geometric sequence formula is given as follows;
Where;
M = The monthly payment
P = The initial loan balance = $34,006.00
r = The annual interest rate = 9.1%
n = The number of monthly payment = 7 × 12 = 84
Aₙ = The amount remaining= 0 at the end of the given time for payment
Substituting the values into the above formula, , we get;
Therefore, the approximate monthly payment = $548.85