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3 years ago

If AB = 11, BC = 16 and CA = 14, list the angles of ABC in order from smallest to largest.

Mathematics

1 answer:

makvit [3.9K]3 years ago

5 0

Answer:

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How many negative roots will this function have? f(x) = x^7 – 2x^4 + 7x^2 + 2x – 2<br> help plsss

Vikentia [17]

There are two negative roots to the provided polynomial function

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

$\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n$

We have a polynomial function:

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

$\rm f(x) =\left(x+1\right)\left(x^6-x^5+x^4-3x^3+3x^2+4x-2\right)$

Using the zero product property:

$\rm \left x+1\right = 0 \ \ \ or \left x^6-x^5+x^4-3x^3+3x^2+4x-2\right = 0$

After solving:

x = -1, x = -0.853, and x = 0.418 (using the graph method)

Thus, there are two negative roots to the provided polynomial function

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

Learn more about Polynomial here:

brainly.com/question/17822016

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7 0

2 years ago

Find DEA in Circle R. *

Gnesinka [82]

ANSWER:

the answer 130

Step-by-step explanation:

5 0

3 years ago

Can anyone help me find the area of these two pls ?

Rasek [7]

13: 72.25
14: 52
For 14, you need to split the figure into a triangle and rectangle.

5 0

2 years ago

What is the area of the following trapezoid

nignag [31]

Answer:

d. 130

Step-by-step explanation:

3 0

2 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago