3 years ago

Consider the irrational number

Mathematics

1 answer:

blagie [28]3 years ago

3 0

I assume you mean $\sqrt{73}$ , not $73$ , which is not irrational.

Notice that $\sqrt{64}$ . This means $8$ .

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3 years ago

Read 2 more answers

The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?

Alexxx [7]

Answer:

Perimeter = 22.809836694575

Step-by-step explanation:

A(-2, 2) ; B(6,2) ; C(0, 8)

$AB=\sqrt{\left( 6--2\right)^{2} +\left(2-2 \right)^{2} } =\sqrt{64} =8$