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trasher [3.6K]
2 years ago
9

Solve by using substitution x=3y-1 x+2y=9

Mathematics
1 answer:
kogti [31]2 years ago
3 0

Answer:

x=3y−1x=3y-1

x+2y=9x+2y=9

Replace all occurrences of xx with 3y−13y-1 in each equation.

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Replace all occurrences of xx in x+2y=9x+2y=9 with 3y−13y-1.

(3y−1)+2y=9(3y-1)+2y=9

x=3y−1x=3y-1

Add 3y3y and 2y2y.

5y−1=95y-1=9

x=3y−1x=3y-1

Solve for yy in the first equation.

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Move all terms not containing yy to the right side of the equation.

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Add 11 to both sides of the equation.

5y=9+15y=9+1

x=3y−1x=3y-1

Add 99 and 11.

5y=105y=10

x=3y−1x=3y-1

Divide each term by 55 and simplify.

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Divide each term in 5y=105y=10 by 55.

5y5=1055y5=105

x=3y−1x=3y-1

Cancel the common factor of 55.

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Cancel the common factor.

5y5=1055y5=105

x=3y−1x=3y-1

Divide yy by 11.

x=5,y=2

Step-by-step explanation:

please mark me as brainliest thank you

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