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salantis [7]
3 years ago
9

Can someone help on this question plz

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

what is this que bro i don't see bro

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147 is 3/2 of an original amount. What is the original amount
Dovator [93]

Answer:

98

Step-by-step explanation:

147/3=49x2=98

8 0
3 years ago
Find the average rate of change of the function over the given intervals. f(x) = 12x3 + 12; [5,7]
AlladinOne [14]
<span>average rate of change = (f(7) - f(5)) / (x7 - x5)
</span>f(7) = <span>12 (7^3) + 12 = 4128
f(5) = </span>12 (5^3) + 12 = 1512

so
average rate of change = (4128 - 1512)/(7-5)
average rate of change = 2616 / 2
average rate of change = 1308

hope it helps
7 0
3 years ago
Help now fast please
Damm [24]

Answer:

3/4 or .75

Step-by-step explanation:

slope = dy/dx

dy = 1 - -2 = 3

dx = 2 - -2 = 4

slope = 3/4

3 0
3 years ago
Read 2 more answers
Solve for the value of v.
DanielleElmas [232]

Answer:

V=14

Step-by-step explanation:

Well its a supplementary angle if you add everything together.

We know theres a 90 degrees angle and a 34 degree angle.

90+34=124

124+4v=180

Since if you add everything up its a straight line

Solve the equation normally

56=4v

14=v

4 0
3 years ago
Read 2 more answers
A study of 40 English composition professors showed that they spent, on average, 13 minutes correcting a student's term paper. T
photoshop1234 [79]

Answer:

a)

90% confidence interval for the mean grading time of all composition papers.

(12.47981 , 13.52019)

b)

Appropriate inequality

The interval is  ( 12.47981 < μ < 13.52019)

Step-by-step explanation:

<u><em>Explanation</em></u>:-

a)

Given sample size 'n' = 40

Mean of the sample = 13 minutes

standard deviation = 2 min

level of significance = 0.10 or 90%

90% confidence interval for the mean grading time of all composition papers.

( x^{-} - Z_{0.1} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.10} \frac{S.D}{\sqrt{n} } )

 ( 13 - 1.645 \frac{2}{\sqrt{40} } , 13 +1.645 \frac{2}{\sqrt{40} } )

( 13 - 0.52019 , 13 + 0.52019)

(12.47981 , 13.52019)

b)

The interval is  ( 12.47981 < μ < 13.52019)

7 0
3 years ago
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