Can someone help on this question plz

Mathematics

1 answer:

LUCKY_DIMON [66]4 years ago

7 0

Answer:

what is this que bro i don't see bro

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Container A has radius r and height h . It holds a maximum of 44 ounces of water. Container B has radius 2.5r and height 4h .

Dennis_Churaev [7]

Set an equation:

$\pi r^{2} h$ =44
divide both sides by 3.14
$r^{2} h$ =14

$\pi (2.5r)^{2} 4h=x$
divide both sides by 6.25, 4, and 3.14
$r^{2} h$ =x/78.5

Since these two equations are equal, we can set them up that way.

x/78.5=14
multiply both sides by 78.5
x=1099

Answer: The maximum amount of water that container B can hold is 1,099 ounces.

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4 years ago

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When you multiply a pair of conjugates you get a real number

marusya05 [52]

Answer: The complex conjugate has a very special property. Consider what happens when we multiply a complex number by its complex conjugate. We find that the answer is a purely real number it has no imaginary part. This always happens when a complex number is multiplied by its conjugate the result is real number.

Real numbers can be positive or negative, and include the number zero. They are called real numbers because they are not imaginary, which is a different system of numbers

Step-by-step explanation: Every complex number has a complex conjugate. The complex conjugate of a + bi is a - bi. For example, the conjugate of 3 + 15i is 3 - 15i, and the conjugate of 5 - 6i is 5 + 6i.

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3 years ago

Product of (2+x) and (2-x) is

mafiozo [28]

Use FOIL,

$(2+x)(2-x)=4-2x+2x-x^2=4-x^2$ .

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3 years ago

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Integration: How would I get to this answer?

Scrat [10]

Given that $y$ attains a maximum at $x=1$ , it follows that $y'=0$ at that same point. So integrating once gives

$\displaystyle\int\frac{\mathrm d^2y}{\mathrm dx^2}\,\mathrm dx=\int-8x\,\mathrm dx$
$\dfrac{\mathrm dy}{\mathrm dx}=-4x^2+C_1$
$\implies -4(1)^2+C_1=0\implies C_1=4$

and so the first derivative is $y'=-4x^2+4$ .

Integrating again, you get

$\displaystyle\int\frac{\mathrm dy}{\mathrm dx}\,\mathrm dx=\int(-4x^2+4)\,\mathrm dx$
$y=-\dfrac43x^3+4x+C_2$

You know that this curve passes through the point (2, -1), which means when $x=2$ , you have $y=-1$ :

$-1=-\dfrac43(2)^3+4(2)+C_2$
$\implies C_2=\dfrac53$

and so

$y=-\dfrac43x^3+4x+\dfrac53$