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Rus_ich [418]
3 years ago
7

Given the pre-image ABCD and the image after a dilation, A'B'C'D', what is true about the polygons? Check all that apply.

Mathematics
2 answers:
Maslowich3 years ago
8 0

Answer:

The length AB is 2.

The length A'B' is 3.

The image is smaller than the pre-image.

The scale factor is Three-halves.

The scale factor is Two-thirds.

Step-by-step explanation:

rodikova [14]3 years ago
6 0

Answer:

A,B,andE

Step-by-step explanation:

Or The length AB is 2, The length A'B' is 3, and The scale factor is Two-Thirds

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  1. yes,
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Which polynomial is in standard form? A) 26x^5+12x^7-8x^3+6x
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It's C.  In order to be in standard form you have to have all your exponents in descending order.  They don't all have to be there in order, the ones that are just have to go from highest to lowest.
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If 2(x + 3) + 7x = 3(x - 2) - 9, then x = ?
Fudgin [204]

Answer:

x=− 7 over 2 =−3.500

Hope this helps!

5 0
3 years ago
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(6h + 8) - (3h + 2) = 15<br> PLEASE HELP I ALSO NEED TO SHOW WORK
Anestetic [448]

Answer:

h=3

Step-by-step explanation:

So we have the equation:

(6h+8)-(3h+2)=15

First, let's distribute the negative:

(6h+8)+(-3h-2)=15

Combine like terms:

(6h-3h)+(8-2)=15

Subtract or add:

3h+6=15

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3h=9

Divide both sides by 3:

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And we're done!

5 0
3 years ago
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You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us
Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that    

step 1

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

r=10\%=10/100=0.10\\n=4  

substitute in the formula above

A=P(1+\frac{0.10}{4})^{4t}  

A=P(1.025)^{4t}  

Applying property of exponents

A=P[(1.025)^{4}]^{t}  

A=P(1.1038)^{t}  

step 2

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

r=10\%=10/100=0.10  

substitute in the formula above

A=P(e)^{0.10t}  

Applying property of exponents

A=P[(e)^{0.10}]^{t}  

A=P(1.1052)^{t}  

step 3

Compare the final amount

P(1.1052)^{t} > P(1.1038)^{t}

therefore

Find the difference

P(1.1052)^{t} - P(1.1038)^{t} ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0
3 years ago
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