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mart [117]
4 years ago
9

Horizontal tangents at = 0.2 = 1 and 2 =3. Let gbe the function defined by

Mathematics
1 answer:
IRINA_888 [86]4 years ago
6 0

Answer:5654

Step-by-step explanation:

6655544

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Line BD is tangent to circle O at C, Arch AEC = 299, and ACE = 93. Find Angle DCE.
VladimirAG [237]
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get  A=180-(E+93)

So, by alternate segment theorem, DCE= A.

thats all i can say.
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3 years ago
Which of the graphed systems share the same solution set?
TEA [102]

It is the graph where the two lines intersect, when they intersect there is a point where they connect, and that is your answer

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4 years ago
Read 2 more answers
Find the midpoint of each line segment
devlian [24]

Answer:

(\frac{7}{2},\frac{1}{2})

Step-by-step explanation:

For this you use the midpoint formula

(\frac{x_{2} +x_{1} }{2} ,\frac{y_{2} +y_{1} }{2} )

the points would be (2,1) and (5,2)

The midpoint would be (\frac{7}{2},\frac{1}{2})

5 0
2 years ago
Please help I don’t understand 6 - z+3y+5x^2
ale4655 [162]

Answer:

what is the complete question?

6 0
3 years ago
Point A is located at (-2, 2), and point M is located at (1,0). If point M is the midpoint of AB, find the location of point B.
bezimeni [28]

Answer:

B. B = (4,-2)

Step-by-step explanation:

GIven that A = (-2, 2) and M = (1, 0), and that point M is the midpoint of AB, the midpoint can be determined as a vectorial sum of A and B. That is:

M = \frac{1}{2}\cdot A + \frac{1}{2}\cdot B

The location of B is now determined after algebraic handling:

\frac{1}{2}\cdot B = M - \frac{1}{2}\cdot A

B = 2\cdot M -A

Then:

B = 2\cdot (1,0)-(-2,2)

B = (2\cdot 1, 2\cdot 0)-(-2,2)

B = (2,0) -(-2,2)

B = (4,-2)

Which corresponds to option B.

5 0
3 years ago
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