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torisob [31]
3 years ago
13

Plz help on numbers 18-20 with work and answer shown plz

Mathematics
1 answer:
otez555 [7]3 years ago
7 0
Hope this helps! If there's any question then leave a comment.

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A circle is shown. Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W.
Marat540 [252]

<u>Given</u>:

Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W. Secant T V intersects the circle at point U.

The length of TU is (y - 2).

The length of UV is 8.

The length of SW is (y + 4)

The length of WV is 6.

We need to determine the length of line segment SV.

<u>Value of y:</u>

The value of y can be determined using the intersecting secant theorem.

Applying, the theorem, we get;

WV \times SV=UV \times TV

Substituting the values, we have;

6 \times (y+4+6)=8 \times (y-2+8)

   6 \times (y+10)=8 \times (y+6)

          6y+60=8y+48

        -2y+60=48

               -2y=-12

                   y=6

Thus, the value of y is 6.

<u>Length of SV:</u>

The length of SV is given by

SV=SW+WV

SV=y+4+6

SV=6+4+6

SV=16

Thus, the length of SV is 16 units.

Hence, Option D is the correct answer.

7 0
3 years ago
Read 2 more answers
Emma has 53 marbles.she gets some marbles from Fred.then she gives 10 marbles to tessie.she now has 58 marbles how many marbles
nata0808 [166]
53+n=(58+10)
n=15
emma got 15 marbles from fred

8 0
3 years ago
By [n][n] we denote the set {1,…,n}. A function f:[m]→[n] is called monotone if f(i) \leq f(j)f(i)≤f(j)whenever i &lt; ji
Dafna11 [192]

Answer:

There are a total of  { 6 \choose 3} = 20 functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

{6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20  

3 0
3 years ago
X + y = 0<br> x - y = 4 <br> Then what does x =
mylen [45]
X - (-x) = 4
2x = 4

x=2
8 0
3 years ago
[(e^x -e^-x)/(e^x + e^-x)] = 1/3​
mr_godi [17]

Answer:

x ≈ 0.34657359

Step-by-step explanation:

5 0
3 years ago
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