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2 years ago

Can someone help me on this. The solution to -45 = n/5 is _____. -9 9 225 -225

Mathematics

1 answer:

Oliga [24]2 years ago

3 0

Answer:

the answer is -225

you have to undo the operation that is being done to x. since it's dividing, you have to multiply both sides by 5 to "undo" what had been done. 5*-45= -225

Step-by-step explanation:

i hope this helped :)

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In AABC, a = 8, b = 5, and c = 9. What is the value of<br> angle B.

FromTheMoon [43]

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3 years ago

WILL GIVE 20 POINTS

Oksanka [162]

Answer:

The answer is B

Step-by-step explanation:

75 + x = 90

First, Virginia had to write an equation to solve for x.

75 - 75 + x = 90 - 75

Second, Virginia used the subtraction property of equality to isolate x.

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Third, "x = 15" was the answer Virginia got after subtracting 90 and 75.

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2 years ago

What is the order of 4 x 10^-7, 7 x 10^-9, 1 x 10^4, 2 x 10^4

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2 years ago

Read 2 more answers

What are the coordinates of the endpoints of the mid segment of triangle ABC that is parallel to line AB?

MrMuchimi

Answer:

$(4.5,4)$ and $(4.5,6.5)$

Step-by-step explanation:

we have the coordinates

A(2,7),B(2,2),C(7,6)

we know that

The mid segment of triangle ABC that is parallel to line AB is located between the mid point AC and the mid point BC

The formula to calculate the midpoint between two points is equal to

$(\frac{x1+x2}{2},\frac{y1+y2}{2})$

step 1

Find the mid point AC

we have

A(2,7),C(7,6)

substitute in the formula

$(\frac{2+7}{2},\frac{7+6}{2})$

$(4.5,6.5)$

step 2

Find the mid point BC

we have

B(2,2),C(7,6)

substitute in the formula

$(\frac{2+7}{2},\frac{2+6}{2})$

$(4.5,4)$

therefore

The endpoints of the mid segment of triangle ABC that is parallel to line AB are $(4.5,4)$ and $(4.5,6.5)$

8 0

3 years ago

Write the polynomial f(x)=x^4-10x^3+25x^2-40x+84. In factored form

Verizon [17]

<h2>Steps:</h2>

So firstly, to factor this we need to first find the potential roots of this polynomial. To find it, the equation is $\pm \frac{p}{q}$ , with p = the factors of the constant and q = the factors of the leading coefficient. In this case:

$\textsf{leading coefficient = 1, constant = 84}\\\\p=1,2,3,4,6,7,12,14,21,28,42,84\\q=1\\\\\pm \frac{1,2,3,4,6,7,12,14,21,28,42,84}{1}\\\\\textsf{Potential roots =}\pm 1, \pm 2,\pm 3,\pm 4,\pm 6, \pm 7,\pm 12,\pm 14,\pm 21,\pm 28,\pm 42,\pm 84$

Next, plug in the potential roots into x of the equation until one of them ends with a result of 0:

$f(1)=(1)^4-10(1)^3+25(1)^2-40(1)+84\\f(1)=1-10+25-40+84\\f(1)=60\ \textsf{Not a root}\\\\f(2)=2^4-10(2)^3+25(2)^2-40(2)+84\\f(2)=16-10*8+25*4-80+84\\f(2)=16-80+100-80+84\\f(2)=80\ \textsf{Not a root}\\\\f(3)=3^4-10(3)^3+25(3)^2-40(3)+84\\f(3)=81-10*27+25*9-120+84\\f(3)=81-270+225-120+84\\f(3)=0\ \textsf{Is a root}$

Since we know that 3 is a root, this means that one of the factors is (x - 3). Now that we know one of the roots, we are going to use synthetic division to divide the polynomial. To set it up, place the root of the divisor, in this case 3 from x - 3, on the left side and the coefficients of the original polynomial on the right side as such:

3 | 1 - 10 + 25 - 40 + 84
_________________

Firstly, drop the 1:

3 | 1 - 10 + 25 - 40 + 84
↓
_________________
1

Next, multiply 3 and 1, then add the product with -10:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3
_________________
1 - 7

Next, multiply 3 and -7, then add the product with 25:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21
_________________
1 - 7 + 4

Next, multiply 3 and 4, then add the product with -40:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12
_________________
1 - 7 + 4 - 28

Lastly, multiply -28 and 3, then add the product with 84:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12 - 84
_________________
1 - 7 + 4 - 28 + 0

Now our synthetic division is complete. Now since the degree of the original polynomial is 4, this means our quotient has a degree of 3 and follows the format $ax^3+bx^2+cx+d$ . In this case, our quotient is $x^3-7x^2+4x-28$ .

So right now, our equation looks like this:

$f(x)=(x-3)(x^3-7x^2+4x-28)$

However, our second factor can be further simplified. For the second factor, I will be factoring by grouping. So factor x³ - 7x² and 4x - 28 separately. Make sure that they have the same quantity inside the parentheses:

$f(x)=(x-3)(x^2(x-7)+4(x-7))$

Now it can be rewritten as:

$f(x)=(x-3)(x^2+4)(x-7)$

<h2>Answer:</h2>

Since the polynomial cannot be further simplified, your answer is:

$f(x)=(x-3)(x^2+4)(x-7)$

6 0

2 years ago