Answer:An iodide ion is the ion I−. Compounds with iodine in formal oxidation state −1 are called iodides. This page is for the iodide ion and its salts, not organo iodine compounds. In everyday life, iodide is most commonly encountered as a component of iodized salt, which many governments mandate.
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When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.
<h3>What is a precipitate?</h3>
The precipitate is the solid concentration of a substance that is collected over a solution.
First, we determine the concentration of magnesium and hydroxide
(Mg2+) = 7.00 × 10⁻⁴
(OH−) = 5.00 × 10⁻⁵
Now, we calculate the solubility quotient
Qc = (Mg2+) (OH−) ²
Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²
Qc = 1.75 x 10⁻¹²
The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.
Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.
To learn more about precipitate, refer to the below link:
brainly.com/question/16950193
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<h3><u>Answer;</u></h3>
Molarity = 0.25 M
<h3><u>Explanation;</u></h3>
Molarity is given by moles/Liter.
First we find moles:
Number of moles = Mass /molar mass
= (10.7g NH4Cl)/(53.5g/mol NH4Cl)
= 0.200 moles NH4Cl
Then we convert to liters:
= (800mL)*(1L/1000mL) = 0.800L
Therefore; molarity = 0.2moles/0.8L
= 0.25M
Answer with Explanation:
Different versions of a gene are called alleles. Alleles are described as either dominant or recessive depending on their associated traits. Since human cells carry two copies of each chromosome they have two versions of each gene.
I believe it’s cold receptor
