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e-lub [12.9K]
3 years ago
5

The carbon dioxide exhaled by astronauts can be removed from a spacecraft by reacting it with lithium hydroxide (LiOH). The reac

tion is as follows: CO2 (g) + 2LiOH (s) Li2CO3 (s) + H2O (l). An average person exhales about 20 moles of CO2 per day. How many moles of LiOH would be required to maintain two astronauts in a spacecraft for three days?
Chemistry
1 answer:
maks197457 [2]3 years ago
8 0
Two astronauts would exhale about 40 moles of carbon dioxide daily.

Carbon dioxide reacts with lithium hydroxide in a 1 : 2 mole ratio. Set up a proportion:

 1 : 2 = 40 : x

Then, find x: <span>12=40x

</span> Cross multiply. x = 80 moles of LiOH per day for both astronauts
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