The golden rule is to head for cover.
Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol = ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D)
= ![\frac{density \times volume}{molar mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bdensity%20%5Ctimes%20volume%7D%7Bmolar%20mass%7D)
= ![\frac{1.1088 \times 50}{62 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B1.1088%20%5Ctimes%2050%7D%7B62%20g%2Fmol%7D)
= 0.894 mol
Hence, number of moles of water = ![\frac{50 \times 0.998}{18}](https://tex.z-dn.net/?f=%5Cfrac%7B50%20%5Ctimes%200.998%7D%7B18%7D)
= 2.77
As glycol is dissolved in water.
So, the molality = ![0.894 \times \frac{1000}{49.92}](https://tex.z-dn.net/?f=0.894%20%5Ctimes%20%5Cfrac%7B1000%7D%7B49.92%7D)
= 17.9
Therefore, the expected freezing point = ![-1.86 \times 17.9](https://tex.z-dn.net/?f=-1.86%20%5Ctimes%2017.9)
= ![-33.31^{o}C](https://tex.z-dn.net/?f=-33.31%5E%7Bo%7DC)
Thus, we can conclude that the expected freezing point is
.