How might the biodiversity of a mowed lawn compare to that of huge weedy field?

Chemistry

1 answer:

Dennis_Churaev [7]2 years ago

5 0

Answer: The mowed lawn is the one from where the grasses are removed by using the machines or tools.

Explanation:

The mowed lawn is expected to have low number of species as the grasses may be few or scanty thus can support the population of few species like insects, mice, birds, and small number of grazing animals. On the other hand the weedy field can be hub of insects, reptiles like snakes, small mammals, and large mammals. Large weed field can provide food, and habitat to the large number of species. This will support the increase in biodiversity as compared to the mowed lawn.

You might be interested in

The ship that will transport the terranauts to the core is built of what material?A. Cobalt B. Diamond C. Kryptonite D. Unobtain

Veseljchak [2.6K]

Answer:

Explanation:

Ketcher 01232019462D 1 1.00000 0.00000 0 5 4 0 0 0 999 V2000 -0.0330 2.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 0.8330 2.7250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1.6990 2.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 0.8330 3.7250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1.6990 1.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1 2 1 0 0 0 2 3 1 0 0 0 2 4 1 0 0 0 3 5 1 0 0 0 M END

4 0

3 years ago

If i initially have 4.0 l of a gas at a pressure of 1.1 atm, what will the volume be if i increase the pressure of 3.4 atm?

ddd [48]

The volume of a gas that its pressure increase to 3.4 atm is calculated as follows

By use of boyles law that is P1V1=P2V2
V1=4.0 L
P1=1.1 atm
P2=3.4 atm
V2= P1V1/P2

(1.1 atm x 4.0 L)/3.4 atm= 1.29 L

4 0

2 years ago

An archaeologist discovered some charcoal at an excavation site. He sent the samples to a lab for C-14 dating, knowing that the

klio [65]

Here we assume that disintegration has occur so the normal t½ formular will not be used
mathematically we..⅛×5600 =700
therefore it is about 700years option A

7 0

3 years ago

The difference in interchain stability between the polysaccharides glycogen and cellulose is due to: Group of answer choices the

denis-greek [22]

Answer: both the different glycosidic linkages of the molecules and the different hydrogen bonding partners of the individual chains.

Explanation:

Glycogen is a polysaccharide of glucose which is a form of energy storage in fungi, bacteria and animals. Glycogen is primarily stored in the liver cells and skeletal muscle.

The difference in interchain stability between the polysaccharides glycogen and cellulose is due to the different glycosidic linkages of the molecules and the different hydrogen bonding partners of the individual chains.

7 0

2 years ago

Will the calculated Molarity of NaOH be too high or too low or unaffected if the following happen: when you answer the question,

vodomira [7]

Answer:

Explanation:

The result will be affected.

The mass of KHP weighed out was used to calculate the moles of KHP weighed out (moles = mass/molar mass).

Not all the sample is actually KHP if the KHP is a little moist, so when mass was used to determine the moles of KHP, a higher number of moles than what is actually present would be obtained (because some of that mass was not KHP but it was assumed to be so. Therefore, there is actually a less present number of moles than the certain number that was thought of.

During the titration, NaOH reacts in a 1:1 ratio with KHP. So it was determined that there was the same number of moles of NaOH was the volume used as there were KHP in the mass that was weighed out. Since there was an overestimation in the moles of KHP, then there also would be an overestimation in the number of moles of NaOH.

Thus, NaOH will appear at a higher concentration than it actually is.

7 0

3 years ago